On 08-01-2013, at 22:00, Berend Hasselman <bhh at xs4all.nl> wrote: > …... > David implemented the condition by multiplying by x[1]<x[2] which in a numeric context is 0 when x[1]<x[2] en 1 when x[1]>=x[2]. OOPS!! Reverse the 0 and the 1 in that sentence (TRUE becomes 1 and FALSE becomes 0) Berend