[R] vector question

[arun]

HI Andras,
Sorry, I misunderstood your question:

Try this:
 sapply(sapply(b,function(x) d[x<d]),`[`,1)
#[1] 12 36 36




----- Original Message -----
From: Andras Farkas <motyocska at yahoo.com>
To: arun <smartpink111 at yahoo.com>
Cc: 
Sent: Monday, June 17, 2013 2:48 PM
Subject: Re: [R] vector question

Arun,

thank you. Looking at it I am wondering if there is a way to get 36 in the result instead of the 24. The 2nd value in b is 24.6, therefore the 1st value greater then that in d is 36.

appreciate the help,

Andras

--- On Mon, 6/17/13, arun <smartpink111 at yahoo.com> wrote:

> From: arun <smartpink111 at yahoo.com>
> Subject: Re: [R] vector question
> To: "Andras Farkas" <motyocska at yahoo.com>
> Cc: "R help" <r-help at r-project.org>
> Date: Monday, June 17, 2013, 2:45 PM
> May be this helps:
> 
> d[cumsum(sapply(d,function(x) any(x>b)))>=1]
> #[1] 12 24 36
> A.K.
> 
> 
> ----- Original Message -----
> From: Andras Farkas <motyocska at yahoo.com>
> To: r-help at r-project.org
> Cc: 
> Sent: Monday, June 17, 2013 2:29 PM
> Subject: [R] vector question
> 
> Dear All,
> 
> would you please help with the following:
> let us say I have: 
> 
> a <-c(0,1,12,13,24,25,36,37)
> b <-c(6,24.6,27)
> #then I extract every 2nd element from "a"
> d <-a[seq(1, length(a), 2)]
> 
> and what I need help with is to extract the 1st value from d
> that is greater than the values in b, so as a result I
> should have "f" as:
> 
> f <-c(12,36,36)
> 
> appreciate the insights,
> 
> thank you,
> 
> Andras
> 
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