[R] Replace element with pattern

arun smartpink111 at yahoo.com
Fri Nov 1 14:09:49 CET 2013



Hi,

Try this:

Lines1 <- readLines(textConnection("Peak Usage    : init:2359296, used:15859328, committed:15892480,max:50331648Current Usage : init:2359296 used:15857920,committed:15892480,max:50331648|-------------------|
Peak Usage    : init:2359296, used:15859328, committed:15892480,max:50331648Current Usage : init:2359296 used:15857920,committed:15892480,max:50331648|-------------------|"))

data.frame(Col1=as.matrix(gsub("(.*?[/|])","\\1",Lines1))) #Assuming that you want to read it from Peak Usage to the first "|":

#If it is from Current Usage to "|"

data.frame(Col1=as.matrix(gsub("^.*(Current.*?[/|]).*","\\1",Lines1)))


A.K.


On Friday, November 1, 2013 4:11 AM, "mohan.radhakrishnan at polarisft.com" <mohan.radhakrishnan at polarisft.com> wrote:
Hi,
         I have a data frame with one column and several rows of the form.

"Peak Usage    : init:2359296, used:15859328, committed:15892480, 
max:50331648Current Usage : init:2359296, used:15857920, 
committed:15892480, max:50331648|-------------------|"

I tested the regex 

Current.*?[\|]

in an online tester which greedily matches upto the first 'pipe' character

Current Usage : init:2359296, used:15857920, committed:15892480, 
max:50331648|

This is what I want.

I tried to replace the entire rows using 

apply( y, 1, function(x) gsub(x,"Current.*?[/|]",x)) which didn't work.

How is this done ? I also want to recursively apply some more patterns one 
by one on the rows till I reduce it to exactly what I want. Is there a way 
to do this without loops ?

Thanks,
Mohan


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