[R] Fortune? [was: Re: quotation marks and scan]

[Ted Harding]

[See in-line below]
On 17-Nov-2013 22:38:30 Rolf Turner wrote:
> 
> (1) The backslashes are not really there; they are an artefact of the R 
> print() function.
> Try cat(u,"\n").  I think this might be an FAQ.
> 
> (2) Is not your problem the fact that your are setting "replacement" 
> equal to the
> thing you are trying to get rid of?  I.e. don't you want
> 
>      v <- gsub(pattern='\"',replacement='',x=u)     ???
> 


> Either I am misunderstanding your intent or you need another cup of coffee.

Is the above line a Fortune?


>      cheers,
> 
>      Rolf
> 
> On 11/18/13 11:07, Erin Hodgess wrote:
>> Dear R People:
>>
>> I'm sure that this is a very simple problem, but I have been wresting with
>> it for some time.
>>
>> I have the following file that has the following one line:
>>
>>   CRS("+init=epsg:28992")
>>
>> Fair enough.  I scan it into R and get the following:
>>
>>> u
>> [1] "CRS(\"+init=epsg:28992\")"
>>> gsub(pattern='\"',replacement='"',x=u)
>> [1] "CRS(\"+init=epsg:28992\")"
>>
>> I need to get rid of the extra quotation marks and slashes.  I've tried all
>> sorts of things, including gsub, as you see,  but no good.
> 
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-------------------------------------------------
E-Mail: (Ted Harding) <Ted.Harding at wlandres.net>
Date: 17-Nov-2013  Time: 23:55:48
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