# [R] A 'good' way to build a matrix from a sequence of integers?

Kevin E. Thorpe kevin.thorpe at utoronto.ca
Wed Oct 16 01:18:55 CEST 2013

```On 10/15/2013 07:11 PM, Stock Beaver wrote:
> # I understand that a good way to build a vector from a sequence of integers,
> # is to use syntax like this:
> myvec = c(1:99)

First, the c() is not needed here.

myvec <- 1:99

works just fine.

>
> # Here is the 'short' version of my question:
> # I want to understand a 'good' way to build a matrix from a sequence of integers.
>
> # If that question is not clear, here is a longer version:
>
> # Here is what I did for a 1D-matrix:
>
> # I pick the sequence 1:3
> # I build a vector:
> vec1x3 = c(1:3)
> vec1x3
> # I transform it into a 1 x 3 matrix:
> m1x3 = matrix(vec1x3, c(length(vec1x3),1))
> m1x3
> #      [,1]
> # [1,]    1
> # [2,]    2
> # [3,]    3
> # >
>
> # That was easy.
>
> # Next I want to expand from a 1 x 3 matrix to a 2 x 9 matrix
> # which contains all combinations of 1:3

I think you want expand.grid.

expand.grid(x1=1:3, x2=1:3)

>
> # So the first 4 rows would look like this:
> # 1 1
> # 1 2
> # 1 3 I call this a rowvec
> # 2 1
>
> # My first idea is write a loop like this:
>
> for (i in 1:3) {
>    for(j in 1:3) {
>      rowvec = c(i,j)
>      # Place rowvec in matrix
>    }
> }
>
> # I'm curious if a skilled R-person would do it differently?
> 	[[alternative HTML version deleted]]
>
>
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> and provide commented, minimal, self-contained, reproducible code.
>

--
Kevin E. Thorpe
Head of Biostatistics,  Applied Health Research Centre (AHRC)
Li Ka Shing Knowledge Institute of St. Michael's
Assistant Professor, Dalla Lana School of Public Health
University of Toronto
email: kevin.thorpe at utoronto.ca  Tel: 416.864.5776  Fax: 416.864.3016

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