[R] Doubt in simple merge

[PIKAL Petr]

Hi

are you really sure that age in Younger is factor? If it was numeric you can post process result of merge to get rid of NA

Younger$age<-as.numeric(as.character(Younger$age))
Warning message:
NAs introduced by coercion
komplet<-merge(Elder, Younger, all=T)
komplet[complete.cases(komplet),]
   ID age
1 ID1  38
2 ID2  35
3 ID3  31
5 ID4  29
6 ID5  21

If it **is** a factor like in your example

> str(Younger)
'data.frame':   3 obs. of  2 variables:
 $ ID : Factor w/ 3 levels "ID3","ID4","ID5": 2 3 1
 $ age: Factor w/ 3 levels "21","29","NA": 2 1 3

you can do it in similar way but not so easy.
Petr


> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of kingsly
> Sent: Friday, January 17, 2014 6:14 AM
> To: r-help at r-project.org
> Subject: Re: [R] Doubt in simple merge
>
> Thank you dear friends.  You have cleared my first doubt.
>
> My second doubt:
> I have the same data sets "Elder" and "Younger". Elder <- data.frame(
>   ID=c("ID1","ID2","ID3"),
>   age=c(38,35,31))
> Younger <- data.frame(
>   ID=c("ID4","ID5","ID3"),
>   age=c(29,21,"NA"))
>
>
>  Row ID3 comes in both data set. It has a value (31) in "Elder" while
> "NA" in "Younger".
>
> I need output like this.
>
> ID    age
> ID1  38
> ID2  35
> ID3  31
> ID4  29
> ID5  21
>
> Kindly help me.
>
>
>
> On Thursday, 16 January 2014 9:16 PM, Marc Schwartz-3 [via R] <ml-
> node+s789695n4683682h69 at n4.nabble.com> wrote:
>
> Not quite:
>
> > rbind(Elder, Younger)
>    ID age
> 1 ID1  38
> 2 ID2  35
> 3 ID3  31
> 4 ID4  29
> 5 ID5  21
> 6 ID3  31
>
> Note that ID3 is duplicated.
>
>
> Should be:
>
> > merge(Elder, Younger, by = c("ID", "age"), all = TRUE)
>    ID age
> 1 ID1  38
> 2 ID2  35
> 3 ID3  31
> 4 ID4  29
> 5 ID5  21
>
>
> He wants to do a join on both "ID" and "age" to avoid duplications of
> rows when the same ID and age occur in both data frames. If the same
> column names (eg "Var") appears in both data frames and are not part of
> the 'by' argument, you end up with Var.x and Var.y in the result.
>
> In the case of two occurrences of the same ID but two different ages,
> if that is possible, both rows would be added to the result using the
> above code.
>
> Regards,
>
> Marc Schwartz
>
>
> On Jan 16, 2014, at 9:04 AM, Frede Aakmann Tøgersen <[hidden email]>
> wrote:
>
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