[R] an incredibly trivial question about nls
peter.langfelder at gmail.com
Tue Jul 1 22:48:49 CEST 2014
On Tue, Jul 1, 2014 at 1:27 PM, Erin Hodgess <erinm.hodgess at gmail.com> wrote:
> Hello R People:
> I'm having a forest/trees location problem with the output of nls.
> If I save the output to an object, and print the object, it shows, amongst
> other things, the residual sum of squares. I would like to get that.
> However, when I look at names or str of the object, I can't find the
> residual sum of squares.
I think you want to look at summary(object), which contains (see
sigma: the square root of the estimated variance of the random error
sigma^2 = 1/(n-p) Sum(R[i]^2),
where R[i] is the i-th weighted residual.
In other words, you probably want summary(object)$sigma^2*(n-p),
perhaps a square root of it, or maybe just the sigma.
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