[R] Error in foo[[1:3]] : recursive indexing failed at level 2

[Bert Gunter]

foo[[1:3]] asks for the 3rd member of the second component of the list
 that is nested within the 1st component of the top level list. You
have no nested sublists, so this is clearly nonsense. You need to
re-read ?"[" or consult The Introduction to R or other online tutorial
to understand the semantics of "[["  with a vector of indices as
argument.

Cheers,
Bert

Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374

"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
Clifford Stoll




On Thu, Jun 26, 2014 at 7:49 PM, ce <zadig_1 at excite.com> wrote:
> Dear all,
>
> I have a list of arrays :
>
> foo<-list(A = c(1,3), B =c(1, 2), C = c(3, 1))
>
>> foo
> $A
> [1] 1 3
>
> $B
> [1] 1 2
>
> $C
> [1] 3 1
>
> I want to use all foo$A , foo$B and foo$C in a test :
>
>> foo$A[1] == 1
> [1] TRUE
>> foo[[1]][1] == 1
> [1] TRUE
>> foo[[1:3]][1] == 1
> Error in foo[[1:3]] : recursive indexing failed at level 2
>
>
> Is there a regular expression I can use ?
>
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