[R] Issue with special assignment operator

[Jeff Newmiller]

Clearly not. I don't know why you think that should be the expected behaviour. They are different variables.
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Sent from my phone. Please excuse my brevity.

On March 17, 2014 12:11:09 AM PDT, AROONALOK PYNE <aroonalok.pyne at gmail.com> wrote:
>Thanks a lot Jeff for the reply. I usually do what you said i.e,
>return a value from the function and save it in the calling
>environment when I call the function, but I just wanted to experiment
>with the special assignment operator. Could you clarify a small doubt
>of mine :
>
>I agree that x refers to the local version inside foo(). But, once I
>do x <<- 8 inside foo() (as done in the code), isn't the local version
>of x supposed to change too?
>
>On 3/17/14, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote:
>> Because x refers to the local version, not the global one.
>>
>> In case you have not read this before, using <<- is a really really
>bad
>> idea. Your code will become confusing and likely be wrong if you
>ignore this
>> warning. Return a value from the function and save it in the calling
>> environment when you call the function.
>>
>---------------------------------------------------------------------------
>> Jeff Newmiller                        The     .....       .....  Go
>Live...
>> DCN:<jdnewmil at dcn.davis.ca.us>        Basics: ##.#.       ##.#.  Live
>Go...
>>                                       Live:   OO#.. Dead: OO#.. 
>Playing
>> Research Engineer (Solar/Batteries            O.O#.       #.O#.  with
>> /Software/Embedded Controllers)               .OO#.       .OO#. 
>rocks...1k
>>
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>>
>> Sent from my phone. Please excuse my brevity.
>>
>> On March 16, 2014 9:06:13 PM PDT, AROONALOK PYNE
><aroonalok.pyne at gmail.com>
>> wrote:
>>>Hi
>>>
>>>Please explain why the function 'foo()' is not printing x as 8 in the
>>>following code :
>>>
>>>> foo <- function(){
>>>+ x <- 10
>>>+ if(x){
>>>+ x <<- 8
>>>+ }
>>>+ print(x)
>>>+ }
>>>> foo()
>>>[1] 10
>>>> x
>>>[1] 8
>>>>
>>
>>