[R] testing whether two character vectors contain (the same) items in the same order

[Federico Calboli]

> On 6 Aug 2015, at 15:40, Bert Gunter <bgunter.4567 at gmail.com> wrote:
> 
> Define "goodness of match" .  For exact matches, see ?"==" , all.equal, etc.

Fair point.  I would define it as a number that tells me how likely it is that the same (noisy) process produced both lists.

BW

F




> 
> Bert
> 
> On Thursday, August 6, 2015, Federico Calboli <federico.calboli at helsinki.fi> wrote:
> Hi All,
> 
> let’s assume I have a vector of letters drawn only once from the alphabet:
> 
> x = sample(letters, 15, replace = F)
> x
>  [1] "z" "t" "g" "l" "u" "d" "w" "x" "a" "q" "k" "j" "f" "n" “v"
> 
> y = x[c(1:7,9:8, 10:12, 14, 15, 13)]
> 
> I would now like to test how good a match y is for x.  Obviously I can transform the letters in numbers and use a rank test, but I was left wondering whether this is the only solution and whether there are more appropriate solutions that are already implemented in R (I am not going to reinvent the wheel if I can avoid it).
> 
> BW
> 
> F
> 
> 
> --
> Federico Calboli
> Ecological Genetics Research Unit
> Department of Biosciences
> PO Box 65 (Biocenter 3, Viikinkaari 1)
> FIN-00014 University of Helsinki
> Finland
> 
> federico.calboli at helsinki.fi
> 
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> 
> -- 
> Bert Gunter
> 
> "Data is not information. Information is not knowledge. And knowledge is certainly not wisdom."
>    -- Clifford Stoll
> 


--
Federico Calboli
Ecological Genetics Research Unit
Department of Biosciences
PO Box 65 (Biocenter 3, Viikinkaari 1)
FIN-00014 University of Helsinki
Finland

federico.calboli at helsinki.fi