[R] F Distribution
Peter Langfelder
peter.langfelder at gmail.com
Mon Dec 21 20:57:42 CET 2015
You want to use qf which gives you the value at a given percentile. pf
gives you the p-value for a given value of F (inverse)
> qf(0.95, 1, 1)
[1] 161.4476
> pf(161.4476, 1, 1)
[1] 0.95
Peter
On Mon, Dec 21, 2015 at 11:51 AM, Robert Sherry <rsherry8 at comcast.net> wrote:
>
> When I use a table, from a Schaum book, I see that for the 95 percentile,
> with v_1 = 1 and v_2 = 1 the value is 161. In the modern era,
> looking values up in a table is less than ideal. Therefore, I would expect R
> to have a function to do this and based upon my
> reading of the documentation, I would expect the following call to get the
> value I expect:
> pf( .95,1, 1)
> However, it produces
> 0.4918373
> Therefore, I conclude that I am using the wrong function. What function
> should I use?
>
> Thanks
> Bob
>
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