[R] about transforming a data.frame

[Bogdan Tanasa]

Hi Jim,

thanks again. now I see : the answer to my previous question seems to be
yes, as "all" functions works on logical vectors ... best wishes,

-- bogdan

On Fri, May 29, 2015 at 4:29 PM, Bogdan Tanasa <tanasa at gmail.com> wrote:

> Thanks a lot Jim. If I may ask one more little question please,
>
> shall I ask the question ""How can I verify that "B1:B2:B3" is paired with
> ALL of the values 2, 4 and 5 ",
>
> regardless of the pairing value (in our case, for the code below, the
> "pairing value" for "B1:B2:B3" is 1, but it can be 2,3,4, etc BUT NOT
> zero),
>
> how could I test for that ? or this is the way that "apply" works for
> "all" argument ?
>
> a good documentation for "apply" function will help too . thanks, and
> happy weekend !
>
> -- bogdan
>
>
> On Fri, May 29, 2015 at 4:21 PM, Jim Lemon <drjimlemon at gmail.com> wrote:
>
>> Hi Bogdan,
>> If you mean "How can I verify that "B1:B2:B3" is paired with all of
>> the values 2, 4 and 5"
>>
>> apply(table(df$col_names,df$CT),1,all)
>>
>> and if you mean "How can I verify that "B1:B2:B3" is paired with at
>> least one of the values 2, 4 and 5"
>>
>> apply(table(df$col_names,df$CT),1,any)
>>
>> Jim
>>
>>
>> Hi Jim,
>>
>> yes, thank you, that is the desired output. one more question please :
>> after using the dataframe :
>>
>> df <- data.frame (row_names = c("B4:B5:B6", "B7:B8:B9", "D4:D5:D6",
>> "D10:D11:D12", "D10:D11:D12", "E10:E11:E12", "A1:A2:A3",
>> "B10:B11:B12"),  col_names = c
>>
>> ("B1:B2:B3","B1:B2:B3","H4:H5:H6","F10:F11:F12","H1:H2:H3","G7:G8:G9","D1:D2:D3","B1:B2:B3"),
>> CT = c(5,2,2,2,2,2,4,4) )
>>
>> and :
>>
>> table(df$row_names,df$CT)
>> table(df$col_names,df$CT)
>>
>> how could I quickly verify that "B1:B2:B3" (for example) hits the CT
>> values of 2,4,5  at least one time ? an example is in
>>
>> table(df$col_names,df$CT) ?
>>
>> thank you very much,
>>
>> -- bogdan
>>
>
>

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