[R] subset by multiple letters condition

[Adams, Jean]

You can use the grepl() function to give you logicals for each criterion,
then combine them as needed.  For example:

# example version of Command
Command <- paste0("_localize_", c("PD","t2","t1_seq", "abc", "xyz",
"PD_t1"))

hasPD <- grepl("PD", Command, fixed=TRUE)
hast1 <- grepl("t1", Command, fixed=TRUE)
hast2 <- grepl("t2", Command, fixed=TRUE)

> Command[hast1]
[1] "_localize_t1_seq" "_localize_PD_t1"

> Command[hasPD]
[1] "_localize_PD"    "_localize_PD_t1"

> Command[hast1 & hasPD]
[1] "_localize_PD_t1"

Jean

On Fri, Apr 22, 2016 at 8:42 AM, ch.elahe via R-help <r-help at r-project.org>
wrote:

>
> Hi all,
>
> I have a data frame df and I want to do subset based on several conditions
> of letters of the names in Command.1)if the names contain PD 2)if the names
> contain t1 3)if the names contain t2 4)if the names contain t1 and PD 5)if
> the names contain t2 and PD 6)otherwise the names would be unknown. I don't
> know how to use grep for all these conditions.
>
>    'data.frame': 36919 obs. of 162 variables
>    $TE                :int 38,41,11,52,48,75,.....
>    $Command           :factor W/2229 levels
> "_localize_PD","_localize_tre_t2","_localize_t1_seq",...
>
>
> Thanks for any help
>
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