The direct answer to your question is to look at ?get and ? assign.
The R-ish answer to your question is to store the data as elements of a
list rather than separate files and use lapply() instead.
Sarah
On Friday, April 22, 2016, <G.Maubach at gmx.de> wrote:
> Hi all,
>
> I would like to use a loop for tasks that occurs repeatedly:
>
> # Groups
> # Umsatz <= 0: 1 (NICHT kaufend)
> # Umsatz > 0: 2 (kaufend)
> for (year in c("2011", "2012", "2013", "2014", "2015")) {
> paste0("Kunden$Kunde_real_", year) <- (paste0("Kunden$Umsatz_", year) <=
> 0) * 1 +
> (paste0("Kunden$Umsatz_", year) >
> 0) * 2
> paste0("Kunden$Kunde_real_", year) <- factor(paste0("Kunden$Umsatz_",
> year),
> levels = c(1, 2),
> labels = c("NICHT kaufend",
> "kaufend"))
> }
>
> This actually does not work due to the fact that the expression
> "paste0("Kunden$Kunde_real_", year)" ist not interpreted as a variable name
> by the R script language interpreter.
>
> Is there a way to assembly variable names on the fly in R?
>
> Regards
>
> Georg
>
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>
--
Sarah Goslee
http://www.stringpage.com
http://www.sarahgoslee.com
http://www.functionaldiversity.org
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