[R] %in% with matrix of lists

[ruipbarradas at sapo.pt]

Hello,

I don't have a solution but see the difference between the two loops below.

for(j in 1:2)
    for(i in 1:2){
        cat(y[i,j], "\n")
        cat(x[i,j][[1]], "\n")
        cat(y[i,j] %in% x[i,j], "\n", "\n")
    }

for(j in 1:2)
    for(i in 1:2){
        cat(y[i,j], "\n")
        cat(x[i,j][[1]], "\n")
        cat(y[i,j] %in% x[i,j][[1]], "\n", "\n")
    }

So apparently y %in% x is equivalent to the first, but you want the second.
Note that the following doesn't work either.

y %in% x[[1]]
[1]  TRUE FALSE FALSE FALSE

Rui Barradas

 

Citando Neal H. Walfield <neal at walfield.org>:

> I have a matrix of lists.  Something along the lists of (but much
> bigger than):
>
> x = array(dim=c(2, 2), data=list())
> x[1,1] = list(1:5)
> x[2,1] = list(6:9)
> x[1,2] = list(10:13)
> x[2,2] = list(14:16)
>
> Each list contains a number of observations/ground truth for a
> particular state.  That is, state <1,1> has observations <1,2,3,4,5>.
> States may have a different number of observations (which is why I'm
> not using an array).
>
> I have another numeric matrix with the same dimensions and I want to
> check if its values occur.  Something along the lines of:
>
> y = array(dim=c(2, 2), data=c(1, 10, 11, 20))
>
> I want to do:
>
> y %in% x
>
> But it doesn't work as hoped.  (I expect: c(T, F, T, F).)
>
> I realize that I can do this with sapply, but I was hoping for a
> faster / smarter solution.  Any ideas?
>
> Thanks!
>
> :) Neal
>
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