[R] Antwort: RE: Antwort: Re: Merging variables
G.Maubach at weinwolf.de
G.Maubach at weinwolf.de
Wed Jun 8 15:55:46 CEST 2016
Hi Petr,
thanks for your reply.
I prepared little example for you:
-- cut --
ds_temp_1 <-
structure(list(
CustId = c(1001, 1002, 1003, 1004, 1005, 1006),
CustName = c("Miller", "Smith", "Doe", "White", "Black",
"Nobody"),
sales = c(100, 500, 300, 50, 700, 10)
),
.Names = c("CustId",
"CustName", "sales"), row.names = c(NA, 6L), class =
"data.frame")
ds_temp_2 <-
structure(
list(
CustId = c(1001, 1002, 1003),
CustName = c("Miller",
"Smith", "Doe"),
CustGroup = c(1, 2, 3)
),
.Names = c("CustId",
"CustName", "CustGroup"),
row.names = c(NA, 3L),
class = "data.frame"
)
ds_merge <- merge(ds_temp_1, ds_temp_2,
by.x = "CustId", all.x = TRUE,
by.y = "CustId", all.y = FALSE)
ds_merge
-- cut --
which gives
ds_merge
CustId CustName.x sales CustName.y CustGroup
1 1001 Miller 100 Miller 1
2 1002 Smith 500 Smith 2
3 1003 Doe 300 Doe 3
4 1004 White 50 <NA> NA
5 1005 Black 700 <NA> NA
6 1006 Nobody 10 <NA> NA
where CustName is split into CustName.x and CustName.y.
What I would like to have is:
ds_merge
CustId CustName sales CustGroup
1 1001 Miller 100 1
2 1002 Smith 500 2
3 1003 Doe 300 3
4 1004 White 50 NA
5 1005 Black 700 NA
6 1006 Nobody 10 NA
That is CustName in a single variable cause the values within that
variable are identical. I guess because of NA for some cases in ds_temp_2
R generates CustName.x and CustName.y.
Is there a simple way of merging a dataset and having R return a single
variable is the values are identical or missing in either one of the
datasets?
Kind regards
Georg
Von: PIKAL Petr <petr.pikal at precheza.cz>
An: "G.Maubach at weinwolf.de" <G.Maubach at weinwolf.de>,
Kopie: "r-help at r-project.org" <r-help at r-project.org>
Datum: 07.06.2016 13:11
Betreff: RE: [R] Antwort: Re: Merging variables
Hi
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of
> G.Maubach at weinwolf.de
> Sent: Tuesday, June 7, 2016 8:19 AM
> To: Michael Dewey <lists at dewey.myzen.co.uk>
> Cc: r-help at r-project.org
> Subject: [R] Antwort: Re: Merging variables
>
> Hi Michael,
>
> yes, I was astonished about this behaviour either. I have worked with
SPSS a
> lot - and that works different.
If you want to join two data frames by common names you can use use
merge(dat1, dat2, ....)
without specifing by. From help page:
By default the data frames are merged on the columns with names they both
have, but separate specifications of the columns can be given by by.x and
by.y. The rows in the two data frames that match on the specified columns
are extracted, and joined together.
>
> I would like to share some of my data. Can you tell me how I can dump a
> dataset in a way that I can post it here as text?
copy result of dput directly to your mail
dput(dat)
structure(list(hz = c(0, 25, 50), vykon = c(0, 11.6, 22.6)), .Names =
c("hz",
"vykon"), row.names = c(NA, -3L), class = "data.frame")
We can use
dat <- structure(list(hz = c(0, 25, 50), vykon = c(0, 11.6, 22.6)), .Names
= c("hz",
"vykon"), row.names = c(NA, -3L), class = "data.frame")
to reconstruct the object.
Regards
Petr
>
> Kind regards
>
> Georg
>
>
>
>
> Von: Michael Dewey <lists at dewey.myzen.co.uk>
> An: G.Maubach at weinwolf.de, r-help at r-project.org,
> Datum: 06.06.2016 15:45
> Betreff: Re: [R] Merging variables
>
>
>
> X-Originating-<%= hostname %>-IP: [217.155.205.190]
>
> Dear Georg
>
> I find it a bit surprising that you end up with customer.x and
customer.y. Can
> you share with us a toy example of two data.frames which exhibit this
> behaviour?
>
> On 06/06/2016 13:29, G.Maubach at weinwolf.de wrote:
> > Hi All,
> >
> > I merged two datasets:
> >
> > ds_merge1 <- merge(x = ds_bw_customer_4_match, y =
> > ds_zww_customer_4_match,
> > by.x = "customer", by.y = "customer",
> > all.x = TRUE, all.y = FALSE)
> >
> > R created a new dataset with the variables customer.x and customer.y.
> > I would like to merge these two variable back together. I wrote a
> > little function (code can be run) for it:
> >
> > -- cut --
> >
> > customer.x <- c("Miller", "Smith", NA, "Bird", NA)
> > customer.y <- c("Miller", NA, "Doe", "Fish", NA)
> > ds_test <- data.frame(customer.x, customer.y, stringsAsFactors =
> > FALSE)
> >
> > t_merge_variables <-
> > function(dataset,
> > var1,
> > var2,
> > merged_var) {
> >
> > # Initialize
> > dataset[[merged_var]] = rep(NA, nrow(dataset))
> > dataset[["mismatch"]] = rep(NA, nrow(dataset))
> >
> > for (i in 1:nrow(dataset)) {
> >
> > # Check 1: var1 missing, var2 missing
> > if (is.na(dataset[[i, var1]]) &
> > is.na(dataset[[i, var2]])) {
> > dataset[["mismatch"]] <- 1 # var1 & var2 are missing
> >
> > # Check 2: var1 filled, var2 missing
> > } else if (!is.na(dataset[[i, var1]]) &
> > is.na(dataset[[i, var2]])) {
> > dataset[[i, merged_var]] <- dataset[[i, var1]]
> > dataset[["mismatch"]] <- 0
> >
> > # Check 3: var1 missing, var2 filled
> > } else if (is.na(dataset[[i, var1]]) &
> > !is.na(dataset[i, var2])) {
> > dataset[[i, merged_var]] <- dataset[[i, var2]]
> > dataset[["mismatch"]] <- 0
> >
> > # Check 4: var1 == var2
> > } else if (dataset[[i, var1]] == dataset[[i, var2]]) {
> > dataset[[i, merged_var]] <- dataset[[i, var1]]
> > dataset[["mismatch"]] <- 0
> >
> > # Leftover: var1 != var2
> > } else {
> > dataset[[i, merged_var]] <- NA
> > dataset[["mismatch"]] <- 2 # var1 != var2
> > } # end if
> > } # end for
> > return(dataset)
> > }
> >
> > ds_var_merge1 <- t_merge_variables(dataset = ds_test,
> > var1 = "customer.x",
> > var2 = "customer.y",
> > merged_var = "customer")
> >
> > ds_var_merge1
> >
> > -- cut --
> >
> > It is executed without error but delivers the wrong values in the
> variable
> > "mismatch". This variable is always 1 although it should be NA, 1 or 2
> > respectively.
> >
> > Can you tell me why the variable is not correctly set?
> >
> > Kind regards
> >
> > Georg
> >
> > ______________________________________________
> > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>
> --
> Michael
> http://www.dewey.myzen.co.uk/home.html
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
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