[R] R column assignment fails for lists
Jim Lemon
drjimlemon at gmail.com
Wed May 4 03:48:13 CEST 2016
Hi Yasil,
If you look at what happens to a[,3] after the "strsplit" it is easy:
> a[,3]
[1] "a,b" "c,d"
Here a[,3] is two strings
a$c <- strsplit(a$c, ",")
> a[,3]
[[1]]
[1] "a" "b"
[[2]]
[1] "c" "d"
Now a[,3] is a two element list. What R probably did was to take the
first component of a[,3] to replace the existing two values. Now if
you don't try to fool R:
> a[,3]<-list(a[,3])
> a$c
[[1]]
[1] "a" "b"
[[2]]
[1] "c" "d"
Jim
On Wed, May 4, 2016 at 9:13 AM, Yasir Suhail <yasir.suhail at gmail.com> wrote:
> Dear R developers and users,
>
> Consider the object :
>
>> a <- data.frame(a=c(1,2), b=c(2,3), c=c("a,b","c,d"), stringsAsFactors = F)
>> a$c <- strsplit(a$c, ",")
>
> Re-assignment works fine for columns 1 and 2, but fails for column 3. If a
> is a valid object, the assignment should work.
>
>> a[,1] <- a[,1]
>> a[,2] <- a[,2]
>> a[,3] <- a[,3]
> Warning message:
> In `[<-.data.frame`(`*tmp*`, , 3, value = list(c("a", "b"), c("c", :
> provided 2 variables to replace 1 variables
>
> [[alternative HTML version deleted]]
>
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