# [R] if else condition - help

Dylan Keenan dylan.keenan at gmail.com
Sun May 22 20:12:31 CEST 2016

```Try this:

> sign(ifelse(abs(k)<=1.5, 0, k))

C1 C2 C3 C4
A  0  0  0  0
B  1  0  0  0
C  0 -1  0  0
D -1  1 -1 -1

On Sun, May 22, 2016 at 2:00 PM Adrian Johnson <oriolebaltimore at gmail.com>
wrote:

> Hi group:
> I am having difficulty with if else condition. I kindly request some help.
>
> I have a matrix k
>
> > k
>            C1         C2         C3         C4
> A  0.09902175 -0.1083887  0.2018689 -0.3546167
> B  1.60623838 -1.4167034  0.9076373 -0.3161138
> C -0.10433133 -1.7060911 -0.4030050  1.0153297
> D -2.91485614  2.9201895 -2.4771802 -2.6991517
>
> I want to convert values > 1.5 to 1, < -1.5 to -1 and rest to 0;
>
> > k1 - desired output
>            C1         C2         C3         C4
> A          0           0            0           0
> B           1          0            0           0
> C           0        -1             0           0
> D           -1        1            -1           -1
>
>
> I am trying with if else but cannot do it. I could only define one
> condition.  Could someone help how I can do this. I dont mean only if
> else, but any other way.
>
> k =
> structure(c(0.0990217544905328, 1.60623837694539, -0.104331330281166,
> -2.91485614212114, -0.108388742328104, -1.41670341534772,
> -1.70609114096417,
> 2.92018951284015, 0.201868946570178, 0.907637296638577, -0.403004972105994,
> -2.47718015803221, -0.354616729237253, -0.316113789733413,
> 1.01532974064126,
> -2.69915170731852), .Dim = c(4L, 4L), .Dimnames = list(c("A",
> "B", "C", "D"), c("C1", "C2", "C3", "C4")))
>
>
>
> k1 <- t(apply(k, 1, function(x) ifelse(x > 1.5,1,-1)))
>
> > k1
>   C1 C2 C3 C4
> A -1 -1 -1 -1
> B  1 -1 -1 -1
> C -1 -1 -1 -1
> D -1  1 -1 -1
>
>
>
> Thanks
>
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