[R] Dynamic reference, right-hand side of function

Love Bohman love.bohman at sociology.su.se
Mon Dec 4 23:20:39 CET 2017


:-)
I don't insist on anything, I'm just struggling to learn a new language and partly a new way of thinking, and I really appreciate the corrections. I hope I someday will be able to handle lists in R as easy as I handle loops in Stata...
Thanks again!

Love
  

-----Ursprungligt meddelande-----
Från: peter dalgaard [mailto:pdalgd at gmail.com] 
Skickat: den 4 december 2017 23:09
Till: Love Bohman <love.bohman at sociology.su.se>
Kopia: r-help at r-project.org
Ämne: Re: [R] Dynamic reference, right-hand side of function

Um, if you insist on doing it that way, at least use

assign(varname, as.vector(get(varname)))

-pd

> On 4 Dec 2017, at 22:46 , Love Bohman <love.bohman at sociology.su.se> wrote:
> 
> Hi!
> Thanks for the replies!
> I understand people more accustomed to R doesn't like looping much, and that thinking about loops is something I do since I worked with Stata a lot. The syntax from Peter Dalgaard was really clever, and I learned a lot from it, even though it didn't solve my problem (I guess it wasn't very well explained). My problem was basically that I have a data matrix consisting of just 1 row, and I want to convert that row into a vector. However, when trying to do that dynamically, I couldn't get R to read the right hand side of the syntax as a variable name instead of a string. However, together with a colleague I finally solved it with the (eval(as.name()) function (I include the loop I used below). I understand that looping isn't kosher among you more devoted R-users, and eventually I hope I will learn to use lists in the future instead.
> 
> Thanks!
> Love
> 
> 
> for (year in 2000:2007){
> varname <- paste0("aa_",year)
> assign(paste0(varname), as.vector(eval(as.name(varname))))
> }
> 
> -----Ursprungligt meddelande-----
> Från: peter dalgaard [mailto:pdalgd at gmail.com]
> Skickat: den 4 december 2017 16:39
> Till: Love Bohman <love.bohman at sociology.su.se>
> Kopia: r-help at r-project.org
> Ämne: Re: [R] Dynamic reference, right-hand side of function
> 
> The generic rule is that R is not a macro language, so looping of names of things gets awkward. It is usually easier to use compound objects like lists and iterate over them. E.g.
> 
> datanames <- paste0("aa_", 2000:2007)
> datalist <- lapply(datanames, get)
> names(datalist) <- datanames
> col1 <- lapply(datalist, "[[", 1)
> colnum <- lapply(col1, as.numeric)
> 
> (The 2nd line assumes that the damage has already been done so that 
> you have aa_2000 ... aa_2007 in your workspace. You might 
> alternatively create the list directly while importing the data.)
> 
> -pd
> 
>> On 4 Dec 2017, at 12:33 , Love Bohman <love.bohman at sociology.su.se> wrote:
>> 
>> Hi R-users!
>> Being new to R, and a fairly advanced Stata-user, I guess part of my problem is that my mindset (and probably my language as well) is wrong. Anyway, I have what I guess is a rather simple problem, that I now without success spent days trying to solve.
>> 
>> I have a bunch of datasets imported from Stata that is labelled aa_2000 aa_2001 aa_2002, etc. Each dataset is imported as a matrix, and consists of one column only. The columns consists of integer numbers. I need to convert the data to vectors, which I found several ways to do. I use, for example:
>> aa_2000 <- as.numeric(aa_2000[,1])
>> However, when trying to automate the task, so I don't have to write a line of code for each dataset, I get stuck. Since I'm a Stata user, my first attempt is trying to make a loop in order to loop over all datasets. However, I manage to write a loop that works for the left-hand side of the syntax, but not for the right-hand side.
>> I have included some examples from my struggles to solve the issue below, what they all have in common is that I don't manage to call for any "macro" (is that only a Stata-word?) in the right hand side of the functions. When I try to replace the static reference with a dynamic one (like in the left-hand side), the syntax just doesn't work.
>> 
>> I would very much appreciate some help with this issue!
>> All the best,
>> Love
>> 
>> year <- 2002
>> dataname <- paste0("aa_",year)
>> assign(paste0(dataname), as.numeric(aa_2002[,1]))
>> 
>> year <- 2003
>> assign(paste0("aa_",year), as.numeric(aa_2003))
>> 
>> year <- 2005
>> assign(paste0("aa_",year), aa_2005[,1])
>> 
>> list1 <- c(2000:2007)
>> list1[c(7)]
>> assign(paste0("aa_",list1[c(7)]), as.numeric(paste0(aa_2006)))
>> 
>> 
>> 	[[alternative HTML version deleted]]
>> 
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> 
> --
> Peter Dalgaard, Professor,
> Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 
> 2000 Frederiksberg, Denmark
> Phone: (+45)38153501
> Office: A 4.23
> Email: pd.mes at cbs.dk  Priv: PDalgd at gmail.com
> 
> 
> 
> 
> 
> 
> 
> 
> 

--
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Office: A 4.23
Email: pd.mes at cbs.dk  Priv: PDalgd at gmail.com











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