[R] for loop in R

[jennifer.sheng2002 at gmail.com]

That is right, Bob.  Only one loop for now, since I do not know how to set up the 2nd loop.  Any advice from the community?  Thank you!

Sent from my iPhone

> On Jan 12, 2017, at 4:49 PM, Robert Sherry <rsherry8 at comcast.net> wrote:
> 
> I only see one for loop in your code. I am wondering if you want a second for loop based upon the length of newdata.
> 
> I would also think that you do not need the second call to set.seed.
> 
> Bob
> 
>> On 1/12/2017 4:44 PM, Jennifer Sheng wrote:
>> Dear friends,  I am working on a double loop using for.  One level of loop
>> is to predict N times for each subject, and the second level is to predict
>> M times for the every subject, one subject after one subject.   Please note
>> every subject have different N or M rows of data.   Any advice?  Thank you
>> so much!
>> 
>> Below is the current code:
>> 
>> set.seed (123)   ## for consistent result;
>> 
>> ND <- S004Cmin[S004Cmin$ID %in% c(1:10),]   # define the first 10 subjects
>> 
>> predSurv <- vector("list", nrow(ND))
>> 
>> for (i in 1:nrow(ND)) {
>> 
>>   set.seed(123)
>> 
>>   predSurv[[i]] <- survfitJM(fitJOINT.NULL, newdata = ND[1:i, ],
>> idVar="USUBJID")
>> 
>>   }
>> 
>> 
>> 
>> Thank you very much!
>> 
>> Jenny
>> 
>>    [[alternative HTML version deleted]]
>> 
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> 
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.