[R] Why is merge sorting even when sort = F?

Rui Barradas ruipbarradas at sapo.pt
Wed Mar 8 18:52:30 CET 2017

```Hello,

If you need to preserve the order you can do it like this.

inx <- order(grades2\$grade)
result <- merge(grades2, info, by = "grade", all.x = T, all.y = F, sort
= FALSE)
result[order(inx), ]

Hope this helps,

Rui Barradas

Em 08-03-2017 16:55, Dimitri Liakhovitski escreveu:
> Thank you. I was just curious what sort=FALSE had no impact.
> Wondering what it is there for then...
>
> On Wed, Mar 8, 2017 at 11:43 AM, Jeff Newmiller
> <jdnewmil at dcn.davis.ca.us> wrote:
>> Merging is not necessarily an order-preserving operation, but sorting can make the operation more efficient. The sort=TRUE argument forces the result to be sorted, but sort=FALSE is in not a promise that order will be preserved. (I think the imperfect sorting occurs when there are multiple keys but am not sure.) You can add columns to the input data that let you restore some semblance of the original ordering afterward, or you can roll your own possibly-less-efficient merge using match and indexing:
>>
>> info[ match( grades2\$grade, info\$grade ), ]
>> --
>> Sent from my phone. Please excuse my brevity.
>>
>> On March 8, 2017 8:07:27 AM PST, Dimitri Liakhovitski <dimitri.liakhovitski at gmail.com> wrote:
>>> Hello!
>>> I have a vector 'grades' and a data frame 'info':
>>>
>>> grades2 <- data.frame(grade = c(1,2,2,3,1))
>>> info <- data.frame(
>>>   grade = 3:1,
>>>   desc = c("Excellent", "Good", "Poor"),
>>>   fail = c(F, F, T)
>>> )
>>>
>>> I want to get the info for all grades I have in info:
>>>
>>> This solution resorts everything in the order of column 'grade':
>>> merge(grades2, info, by = "grade", all.x = T, all.y = F)
>>>
>>> Could you please explain why this solution also resorts - despite sort
>>> = FALSE?
>>> merge(grades2, info, by = "grade", all.x = T, all.y = F, sort = FALSE)
>>>
>>> Thanks a lot!
>
>
>

```

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