[R] dplyr - add/expand rows
Michael Lawrence
lawrence.michael at gene.com
Tue Nov 28 18:49:58 CET 2017
Or with the Bioconductor IRanges package:
df <- with(input, DataFrame(station, year=IRanges(from, to), record))
expand(df, "year")
DataFrame with 24 rows and 3 columns
station year record
<character> <integer> <character>
1 07EA001 1960 QMS
2 07EA001 1961 QMC
3 07EA001 1962 QMC
4 07EA001 1963 QMC
5 07EA001 1964 QMC
... ... ... ...
20 07EA001 1979 QRC
21 07EA001 1980 QRC
22 07EA001 1981 QRC
23 07EA001 1982 QRC
24 07EA001 1983 QRC
If you tell the computer more about your data, it can do more things for
you.
Michael
On Tue, Nov 28, 2017 at 7:34 AM, Martin Morgan <
martin.morgan at roswellpark.org> wrote:
> On 11/26/2017 08:42 PM, jim holtman wrote:
>
>> try this:
>>
>> ##########################################
>>
>> library(dplyr)
>>
>> input <- tribble(
>> ~station, ~from, ~to, ~record,
>> "07EA001" , 1960 , 1960 , "QMS",
>> "07EA001" , 1961 , 1970 , "QMC",
>> "07EA001" , 1971 , 1971 , "QMM",
>> "07EA001" , 1972 , 1976 , "QMC",
>> "07EA001" , 1977 , 1983 , "QRC"
>> )
>>
>> result <- input %>%
>> rowwise() %>%
>> do(tibble(station = .$station,
>> year = seq(.$from, .$to),
>> record = .$record)
>> )
>>
>> ###########################
>>
>
> In a bit more 'base R' mode I did
>
> input$year <- with(input, Map(seq, from, to))
> res0 <- with(input, Map(data.frame, station=station, year=year,
> record=record))
> as_tibble(do.call(rbind, unname(res0)))# A tibble: 24 x 3
>
> resulting in
>
> > as_tibble(do.call(rbind, unname(res0)))# A tibble: 24 x 3
> station year record
> <fctr> <int> <fctr>
> 1 07EA001 1960 QMS
> 2 07EA001 1961 QMC
> 3 07EA001 1962 QMC
> 4 07EA001 1963 QMC
> 5 07EA001 1964 QMC
> 6 07EA001 1965 QMC
> 7 07EA001 1966 QMC
> 8 07EA001 1967 QMC
> 9 07EA001 1968 QMC
> 10 07EA001 1969 QMC
> # ... with 14 more rows
>
> I though I should have been able to use `tibble` in the second step, but
> that leads to a (cryptic) error
>
> > res0 <- with(input, Map(tibble, station=station, year=year,
> record=record))Error in captureDots(strict = `__quosured`) :
> the argument has already been evaluated
>
> The 'station' and 'record' columns are factors, so different from the
> original input, but this seems the appropriate data type for theses columns.
>
> It's interesting to compare the 'specialized' knowledge needed for each
> approach -- rowwise(), do(), .$ for tidyverse, with(), do.call(), maybe
> rbind() and Map() for base R.
>
> Martin
>
>
>
>>
>>
>> Jim Holtman
>> Data Munger Guru
>>
>> What is the problem that you are trying to solve?
>> Tell me what you want to do, not how you want to do it.
>>
>> On Sun, Nov 26, 2017 at 2:10 PM, Bert Gunter <bgunter.4567 at gmail.com>
>> wrote:
>>
>> To David W.'s point about lack of a suitable reprex ("reproducible
>>> example"), Bill's solution seems to be for only one station.
>>>
>>> Here is a reprex and modification that I think does what was requested
>>> for
>>> multiple stations, again using base R and data frames, not dplyr and
>>> tibbles.
>>>
>>> First the reprex with **two** stations:
>>>
>>> d <- data.frame( station = rep(c("one","two"),c(5,4)),
>>>>
>>> from = c(60,61,71,72,76,60,65,82,83),
>>> to = c(60,70,71,76,83,64, 81, 82,83),
>>> record = c("A","B","C","B","D","B","B","D","E"))
>>>
>>> d
>>>>
>>> station from to record
>>> 1 one 60 60 A
>>> 2 one 61 70 B
>>> 3 one 71 71 C
>>> 4 one 72 76 B
>>> 5 one 76 83 D
>>> 6 two 60 64 B
>>> 7 two 65 81 B
>>> 8 two 82 82 D
>>> 9 two 83 83 E
>>>
>>> ## Now the conversion code using base R, especially by():
>>>
>>> out <- by(d, d$station, function(x) with(x, {
>>>>
>>> + i <- to - from +1
>>> + data.frame(YEAR =sequence(i) -1 +rep(from,i), RECORD =rep(record,i))
>>> + }))
>>>
>>>
>>> out <- data.frame(station =
>>>>
>>> rep(names(out),sapply(out,nrow)),do.call(rbind,out), row.names = NULL)
>>>
>>>
>>> out
>>>>
>>> station YEAR RECORD
>>> 1 one 60 A
>>> 2 one 61 B
>>> 3 one 62 B
>>> 4 one 63 B
>>> 5 one 64 B
>>> 6 one 65 B
>>> 7 one 66 B
>>> 8 one 67 B
>>> 9 one 68 B
>>> 10 one 69 B
>>> 11 one 70 B
>>> 12 one 71 C
>>> 13 one 72 B
>>> 14 one 73 B
>>> 15 one 74 B
>>> 16 one 75 B
>>> 17 one 76 B
>>> 18 one 76 D
>>> 19 one 77 D
>>> 20 one 78 D
>>> 21 one 79 D
>>> 22 one 80 D
>>> 23 one 81 D
>>> 24 one 82 D
>>> 25 one 83 D
>>> 26 two 60 B
>>> 27 two 61 B
>>> 28 two 62 B
>>> 29 two 63 B
>>> 30 two 64 B
>>> 31 two 65 B
>>> 32 two 66 B
>>> 33 two 67 B
>>> 34 two 68 B
>>> 35 two 69 B
>>> 36 two 70 B
>>> 37 two 71 B
>>> 38 two 72 B
>>> 39 two 73 B
>>> 40 two 74 B
>>> 41 two 75 B
>>> 42 two 76 B
>>> 43 two 77 B
>>> 44 two 78 B
>>> 45 two 79 B
>>> 46 two 80 B
>>> 47 two 81 B
>>> 48 two 82 D
>>> 49 two 83 E
>>>
>>> Cheers,
>>> Bert
>>>
>>>
>>>
>>>
>>> Bert Gunter
>>>
>>> "The trouble with having an open mind is that people keep coming along
>>> and
>>> sticking things into it."
>>> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>>>
>>> On Sat, Nov 25, 2017 at 4:49 PM, William Dunlap via R-help <
>>> r-help at r-project.org> wrote:
>>>
>>> dplyr may have something for this, but in base R I think the following
>>>>
>>> does
>>>
>>>> what you want. I've shortened the name of your data set to 'd'.
>>>>
>>>> i <- rep(seq_len(nrow(d)), d$YEAR_TO-d$YEAR_FROM+1)
>>>> j <- sequence(d$YEAR_TO-d$YEAR_FROM+1)
>>>> transform(d[i,], YEAR=YEAR_FROM+j-1, YEAR_FROM=NULL, YEAR_TO=NULL)
>>>>
>>>>
>>>> Bill Dunlap
>>>> TIBCO Software
>>>> wdunlap tibco.com
>>>>
>>>> On Sat, Nov 25, 2017 at 11:18 AM, Hutchinson, David (EC) <
>>>> david.hutchinson at canada.ca> wrote:
>>>>
>>>> I have a returned tibble of station operational record similar to the
>>>>> following:
>>>>>
>>>>> data.collection
>>>>>>
>>>>> # A tibble: 5 x 4
>>>>> STATION_NUMBER YEAR_FROM YEAR_TO RECORD
>>>>> <chr> <int> <int> <chr>
>>>>> 1 07EA001 1960 1960 QMS
>>>>> 2 07EA001 1961 1970 QMC
>>>>> 3 07EA001 1971 1971 QMM
>>>>> 4 07EA001 1972 1976 QMC
>>>>> 5 07EA001 1977 1983 QRC
>>>>>
>>>>> I would like to reshape this to one operational record (row) per year
>>>>>
>>>> per
>>>
>>>> station. Something like:
>>>>>
>>>>> 07EA001 1960 QMS
>>>>> 07EA001 1961 QMC
>>>>> 07EA001 1962 QMC
>>>>> 07EA001 1963 QMC
>>>>> ...
>>>>> 07EA001 1971 QMM
>>>>>
>>>>> Can this be done in dplyr easily?
>>>>>
>>>>> Thanks in advance,
>>>>>
>>>>> David
>>>>>
>>>>> [[alternative HTML version deleted]]
>>>>>
>>>>> ______________________________________________
>>>>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>> PLEASE do read the posting guide http://www.R-project.org/
>>>>> posting-guide.html
>>>>> and provide commented, minimal, self-contained, reproducible code.
>>>>>
>>>>>
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>>>>
>>>> ______________________________________________
>>>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>> PLEASE do read the posting guide http://www.R-project.org/
>>>> posting-guide.html
>>>> and provide commented, minimal, self-contained, reproducible code.
>>>>
>>>>
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>>>
>>> ______________________________________________
>>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide http://www.R-project.org/
>>> posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>>
>>>
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>>
>> ______________________________________________
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>> ng-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
>
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