[R] read txt file - date - no space
Diego Avesani
d|ego@@ve@@n| @end|ng |rom gm@||@com
Wed Aug 1 14:37:55 CEST 2018
Dear Pikal, DEar all,
I do not if it could help:
if I print MyData%date, I get (at some point)
[281] "1998-12-10 16:00:00 CET" "1998-12-10 17:00:00 CET"
"1998-12-10 18:00:00 CET" "1998-12-10 19:00:00 CET"
[285] "1998-12-10 20:00:00 CET" "1998-12-10 21:00:00 CET"
"1998-12-10 22:00:00 CET" "1998-12-10 23:00:00 CET"
[289] NA NA NA
NA
[293] NA NA NA
NA
[297] NA NA NA
NA
Again Thanks
Diego
On 1 August 2018 at 14:29, Diego Avesani <diego.avesani using gmail.com> wrote:
> Dear Pikal, Deal all,
>
> again really thank.
>
> it seems not working.
> Some specifications: My non data are -999, but I could change it.
>
> My final results is:
>
> 1 1 -55.86242 -55.84764660 -277.4775
> 2 2 -55.47554 -94.58921682 -277.4845
> 3 3 -55.47095 -99.20239198 -277.4709
> 4 4 -55.46470 -55.45952932 -392.9071
> 5 5 -55.43335 -55.40171682 -388.4110
> 6 6 -55.40108 -55.37399691 -332.9068
> 7 7 -55.39201 -55.35156250 -332.8902
> 8 8 -110.87184 0.16136188 -281.8230
> 9 9 -110.95077 -55.63856096 -332.9564
> 10 10 -157.64430 -0.06602705 -315.3840
> 11 11 -105.06157 0.11507675 -315.4152
> 12 12 -70.08677 -52.54501096 -316.7247
>
>
> So it is not correct.
> For example for the first day in my csv I would have expected 0.167.
>
> I am going to post what you have suggested:
>
> for str(MyData)
>
> 'data.frame': 160008 obs. of 4 variables:
> $ date: POSIXct, format: "1998-01-10 00:00:00" "1998-01-10 01:00:00"
> "1998-01-10 02:00:00" "1998-01-10 03:00:00" ...
> $ str1: num 0.6 0.2 0.6 0 0 0 0 0.2 0.6 0.2 ...
> $ str2: num 0 0.2 0.2 0 0 0 0 0 0.2 0.4 ...
> $ str3: num 0 0.2 0.4 0.6 0 0 0 0 0 0.4 ...
>
> unfortunately, I am not able to post
>
> dput(str[1:20,])
>
> it gives me
>
> Error in str[1:20, ] : object of type 'closure' is not subsettable
>
>
> Thanks again,
> I hope that what I posted could be enough in order to help me.
>
>
>
> Diego
>
>
> On 1 August 2018 at 13:58, PIKAL Petr <petr.pikal using precheza.cz> wrote:
>
>> Hi
>>
>> I did not get through all answers you already got and you probably
>> obtained similar advice as mine.
>>
>> # read data (if you have csv file just use read.csv)
>> > test<-read.table("clipboard", header=T, sep=",")
>>
>> # control your object(s)
>> > str(test)
>> 'data.frame': 8 obs. of 4 variables:
>> $ date: Factor w/ 8 levels "10/1/1998 0:00",..: 1 2 3 4 5 6 7 8
>> $ str1: num 0.6 0.2 0.6 0 0 0 0 0.2
>> $ str2: num 0 0.2 0.2 0 0 0 0 0
>> $ str3: num 0 0.2 0.4 0.6 0 0 0 0
>>
>> #if it is OK change first column to real date by POSIXct
>> test$date<-as.POSIXct(test$date, format="%d/%m/%Y %H:%M")
>>
>> #attach lubridate
>> > library(lubridate)
>>
>> # aggregate your object(s) and use lubridate function
>>
>> > aggregate(test[,-1], list(day(test$date)), mean)
>> Group.1 str1 str2 str3
>> 1 10 0.2 0.05 0.15
>>
>> # or format function
>>
>> > aggregate(test[,-1], list(format(test$date, "%Y-%m-%d")), mean)
>> Group.1 str1 str2 str3
>> 1 1998-01-10 0.2 0.05 0.15
>>
>> If it does not work with your data you should post at least result of
>>
>> str(yourdata)
>>
>> or preferably
>>
>> dput(yourdata[1:20,])
>>
>> Cheers
>> Petr
>>
>>
>> > -----Original Message-----
>> > From: R-help <r-help-bounces using r-project.org> On Behalf Of Diego Avesani
>> > Sent: Wednesday, August 1, 2018 8:55 AM
>> > To: Jeff Newmiller <jdnewmil using dcn.davis.ca.us>
>> > Cc: r-help mailing list <r-help using r-project.org>
>> > Subject: Re: [R] read txt file - date - no space
>> >
>> > Dear all,
>> > I am sorry, I did a lot of confusion. I am sorry, I have to relax and
>> stat all again
>> > in order to understand.
>> > If I could I would like to start again, without mixing strategy and
>> waiting for
>> > your advice.
>> >
>> > I am really appreciate you help, really really.
>> > Here my new file, a *.csv file (buy the way, it is possible to attach
>> it in the
>> > mailing list?)
>> >
>> > date,str1,str2,str3
>> > 10/1/1998 0:00,0.6,0,0
>> > 10/1/1998 1:00,0.2,0.2,0.2
>> > 10/1/1998 2:00,0.6,0.2,0.4
>> > 10/1/1998 3:00,0,0,0.6
>> > 10/1/1998 4:00,0,0,0
>> > 10/1/1998 5:00,0,0,0
>> > 10/1/1998 6:00,0,0,0
>> > 10/1/1998 7:00,0.2,0,0
>> >
>> >
>> > I read it as:
>> > MyData <- read.csv(file="obs_prec.csv",header=TRUE, sep=",")
>> >
>> > at this point I would like to have the daily mean.
>> > What would you suggest?
>> >
>> > Really Really thanks,
>> > You are my lifesaver
>> >
>> > Thanks
>> >
>> >
>> >
>> > Diego
>> >
>> >
>> > On 1 August 2018 at 01:01, Jeff Newmiller <jdnewmil using dcn.davis.ca.us>
>> wrote:
>> >
>> > > ... and the most common source of NA values in time data is wrong
>> > > timezones. You really need to make sure the timezone that is assumed
>> > > when the character data are converted to POSIXt agrees with the data.
>> > > In most cases the easiest way to insure this is to use
>> > >
>> > > Sys.setenv(TZ="US/Pacific")
>> > >
>> > > or whatever timezone from
>> > >
>> > > OlsonNames()
>> > >
>> > > corresponds with your data. Execute this setenv function before the
>> > > strptime or as.POSIXct() function call.
>> > >
>> > > You can use
>> > >
>> > > MyData[ is.na(MyData$datetime), ]
>> > >
>> > > to see which records are failing to convert time.
>> > >
>> > > [1] https://github.com/jdnewmil/eci298sp2016/blob/master/QuickHowto1
>> > >
>> > > On July 31, 2018 3:04:05 PM PDT, Jim Lemon <drjimlemon using gmail.com>
>> > wrote:
>> > > >Hi Diego,
>> > > >I think the error is due to NA values in your data file. If I extend
>> > > >your example and run it, I get no errors:
>> > > >
>> > > >MyData<-read.table(text="103001930 103001580 103001530
>> > > >1998-10-01 00:00:00 0.6 0 0
>> > > >1998-10-01 01:00:00 0.2 0.2 0.2
>> > > >1998-10-01 02:00:00 0.6 0.2 0.4
>> > > >1998-10-01 03:00:00 0 0 0.6
>> > > >1998-10-01 04:00:00 0 0 0
>> > > >1998-10-01 05:00:00 0 0 0
>> > > >1998-10-01 06:00:00 0 0 0
>> > > >1998-10-01 07:00:00 0.2 0 0
>> > > >1998-10-01 08:00:00 0.6 0 0
>> > > >1998-10-01 09:00:00 0.2 0.2 0.2
>> > > >1998-10-01 10:00:00 0.6 0.2 0.4
>> > > >1998-10-01 11:00:00 0 0 0.6
>> > > >1998-10-01 12:00:00 0 0 0
>> > > >1998-10-01 13:00:00 0 0 0
>> > > >1998-10-01 14:00:00 0 0 0
>> > > >1998-10-01 15:00:00 0.2 0 0
>> > > >1998-10-01 16:00:00 0.6 0 0
>> > > >1998-10-01 17:00:00 0.2 0.2 0.2
>> > > >1998-10-01 18:00:00 0.6 0.2 0.4
>> > > >1998-10-01 19:00:00 0 0 0.6
>> > > >1998-10-01 20:00:00 0 0 0
>> > > >1998-10-01 21:00:00 0 0 0
>> > > >1998-10-01 22:00:00 0 0 0
>> > > >1998-10-01 23:00:00 0.2 0 0
>> > > >1998-10-02 00:00:00 0.6 0 0
>> > > >1998-10-02 01:00:00 0.2 0.2 0.2
>> > > >1998-10-02 02:00:00 0.6 0.2 0.4
>> > > >1998-10-02 03:00:00 0 0 0.6
>> > > >1998-10-02 04:00:00 0 0 0
>> > > >1998-10-02 05:00:00 0 0 0
>> > > >1998-10-02 06:00:00 0 0 0
>> > > >1998-10-02 07:00:00 0.2 0 0
>> > > >1998-10-02 08:00:00 0.6 0 0
>> > > >1998-10-02 09:00:00 0.2 0.2 0.2
>> > > >1998-10-02 10:00:00 0.6 0.2 0.4
>> > > >1998-10-02 11:00:00 0 0 0.6
>> > > >1998-10-02 12:00:00 0 0 0
>> > > >1998-10-02 13:00:00 0 0 0
>> > > >1998-10-02 14:00:00 0 0 0
>> > > >1998-10-02 15:00:00 0.2 0 0
>> > > >1998-10-02 16:00:00 0.6 0 0
>> > > >1998-10-02 17:00:00 0.2 0.2 0.2
>> > > >1998-10-02 18:00:00 0.6 0.2 0.4
>> > > >1998-10-02 19:00:00 0 0 0.6
>> > > >1998-10-02 20:00:00 0 0 0
>> > > >1998-10-02 21:00:00 0 0 0
>> > > >1998-10-02 22:00:00 0 0 0
>> > > >1998-10-02 23:00:00 0.2 0 0",
>> > > >skip=1,stringsAsFactors=FALSE)
>> > > >names(MyData)<-c("date","time","st1","st2","st3")
>> > > >MyData$datetime<-strptime(paste(MyData$date,MyData$time),
>> > > > format="%Y-%m-%d %H:%M:%S")
>> > > >MyData$datetime
>> > > >st1_daily<-by(MyData$st1,MyData$date,mean)
>> > > >st2_daily<-by(MyData$st2,MyData$date,mean)
>> > > >st3_daily<-by(MyData$st3,MyData$date,mean)
>> > > >st1_daily
>> > > >st2_daily
>> > > >st3_daily
>> > > >
>> > > >Try adding na.rm=TRUE to the "by" calls:
>> > > >
>> > > >st1_daily<-by(MyData$st1,MyData$date,mean,na.rm=TRUE)
>> > > >st2_daily<-by(MyData$st2,MyData$date,mean,na.rm=TRUE)
>> > > >st3_daily<-by(MyData$st3,MyData$date,mean,na.rm=TRUE)
>> > > >
>> > > >Jim
>> > > >
>> > > >On Tue, Jul 31, 2018 at 11:11 PM, Diego Avesani
>> > > ><diego.avesani using gmail.com> wrote:
>> > > >> Dear all,
>> > > >>
>> > > >> I have still problem with date.
>> > > >> Could you please tel me how to use POSIXct.
>> > > >> Indeed I have found this command:
>> > > >> timeAverage, but I am not able to convert MyDate to properly date.
>> > > >>
>> > > >> Thank a lot
>> > > >> I hope to no bother you, at least too much
>> > > >>
>> > > >>
>> > > >> Diego
>> > > >>
>> > > >>
>> > > >> On 31 July 2018 at 11:12, Diego Avesani <diego.avesani using gmail.com>
>> > > >wrote:
>> > > >>>
>> > > >>> Dear Jim, Dear all,
>> > > >>>
>> > > >>> thanks a lot.
>> > > >>>
>> > > >>> Unfortunately, I get the following error:
>> > > >>>
>> > > >>>
>> > > >>> st1_daily<-by(MyData$st1,MyData$date,mean)
>> > > >>> Error in tapply(seq_len(0L), list(`MyData$date` = c(913L, 914L,
>> > > >925L, :
>> > > >>> arguments must have same length
>> > > >>>
>> > > >>>
>> > > >>> This is particularly strange. indeed, if I apply
>> > > >>>
>> > > >>>
>> > > >>> mean(MyData$str1,na.rm=TRUE)
>> > > >>>
>> > > >>>
>> > > >>> it works
>> > > >>>
>> > > >>>
>> > > >>> Sorry, I have to learn a lot.
>> > > >>> You are really boosting me
>> > > >>>
>> > > >>> Diego
>> > > >>>
>> > > >>>
>> > > >>> On 31 July 2018 at 11:02, Jim Lemon <drjimlemon using gmail.com> wrote:
>> > > >>>>
>> > > >>>> Hi Diego,
>> > > >>>> One way you can get daily means is:
>> > > >>>>
>> > > >>>> st1_daily<-by(MyData$st1,MyData$date,mean)
>> > > >>>> st2_daily<-by(MyData$st2,MyData$date,mean)
>> > > >>>> st3_daily<-by(MyData$st3,MyData$date,mean)
>> > > >>>>
>> > > >>>> Jim
>> > > >>>>
>> > > >>>> On Tue, Jul 31, 2018 at 6:51 PM, Diego Avesani
>> > > ><diego.avesani using gmail.com>
>> > > >>>> wrote:
>> > > >>>> > Dear all,
>> > > >>>> > I have found the error, my fault. Sorry.
>> > > >>>> > There was an extra come in the headers line.
>> > > >>>> > Thanks again.
>> > > >>>> >
>> > > >>>> > If I can I would like to ask you another questions about the
>> > > >imported
>> > > >>>> > data.
>> > > >>>> > I would like to compute the daily average of the different
>> date.
>> > > >>>> > Basically I
>> > > >>>> > have hourly data, I would like to ave the daily mean of them.
>> > > >>>> >
>> > > >>>> > Is there some special commands?
>> > > >>>> >
>> > > >>>> > Thanks a lot.
>> > > >>>> >
>> > > >>>> >
>> > > >>>> > Diego
>> > > >>>> >
>> > > >>>> >
>> > > >>>> > On 31 July 2018 at 10:40, Diego Avesani
>> > > >>>> > <diego.avesani using gmail.com>
>> > > >>>> > wrote:
>> > > >>>> >>
>> > > >>>> >> Dear all,
>> > > >>>> >> I move to csv file because originally the date where in csv
>> > > >file.
>> > > >>>> >> In addition, due to the fact that, as you told me, read.csv is
>> > > >>>> >> a special case of read.table, I prefer start to learn from the
>> > > >>>> >> simplest
>> > > >one.
>> > > >>>> >> After that, I will try also the *.txt format.
>> > > >>>> >>
>> > > >>>> >> with read.csv, something strange happened:
>> > > >>>> >>
>> > > >>>> >> This us now the file:
>> > > >>>> >>
>> > > >>>> >> date,st1,st2,st3,
>> > > >>>> >> 10/1/1998 0:00,0.6,0,0
>> > > >>>> >> 10/1/1998 1:00,0.2,0.2,0.2
>> > > >>>> >> 10/1/1998 2:00,0.6,0.2,0.4
>> > > >>>> >> 10/1/1998 3:00,0,0,0.6
>> > > >>>> >> 10/1/1998 4:00,0,0,0
>> > > >>>> >> 10/1/1998 5:00,0,0,0
>> > > >>>> >> 10/1/1998 6:00,0,0,0
>> > > >>>> >> 10/1/1998 7:00,0.2,0,0
>> > > >>>> >> 10/1/1998 8:00,0.6,0.2,0
>> > > >>>> >> 10/1/1998 9:00,0.2,0.4,0.4
>> > > >>>> >> 10/1/1998 10:00,0,0.4,0.2
>> > > >>>> >>
>> > > >>>> >> When I apply:
>> > > >>>> >> MyData <- read.csv(file="obs_prec.csv",header=TRUE, sep=",")
>> > > >>>> >>
>> > > >>>> >> this is the results:
>> > > >>>> >>
>> > > >>>> >> 10/1/1998 0:00 0.6 0.00 0.0 NA
>> > > >>>> >> 2 10/1/1998 1:00 0.2 0.20 0.2 NA
>> > > >>>> >> 3 10/1/1998 2:00 0.6 0.20 0.4 NA
>> > > >>>> >> 4 10/1/1998 3:00 0.0 0.00 0.6 NA
>> > > >>>> >> 5 10/1/1998 4:00 0.0 0.00 0.0 NA
>> > > >>>> >> 6 10/1/1998 5:00 0.0 0.00 0.0 NA
>> > > >>>> >> 7 10/1/1998 6:00 0.0 0.00 0.0 NA
>> > > >>>> >> 8 10/1/1998 7:00 0.2 0.00 0.0 NA
>> > > >>>> >>
>> > > >>>> >> I do not understand why.
>> > > >>>> >> Something wrong with date?
>> > > >>>> >>
>> > > >>>> >> really really thanks,
>> > > >>>> >> I appreciate a lot all your helps.
>> > > >>>> >>
>> > > >>>> >> Diedro
>> > > >>>> >>
>> > > >>>> >>
>> > > >>>> >> Diego
>> > > >>>> >>
>> > > >>>> >>
>> > > >>>> >> On 31 July 2018 at 01:25, MacQueen, Don <macqueen1 using llnl.gov>
>> > > >wrote:
>> > > >>>> >>>
>> > > >>>> >>> Or, without removing the first line
>> > > >>>> >>> dadf <- read.table("xxx.txt", stringsAsFactors=FALSE,
>> > > >>>> >>> skip=1)
>> > > >>>> >>>
>> > > >>>> >>> Another alternative,
>> > > >>>> >>> dadf$datetime <- as.POSIXct(paste(dadf$V1,dadf$V2))
>> > > >>>> >>> since the dates appear to be in the default format.
>> > > >>>> >>> (I generally prefer to work with datetimes in POSIXct class
>> > > >rather
>> > > >>>> >>> than
>> > > >>>> >>> POSIXlt class)
>> > > >>>> >>>
>> > > >>>> >>> -Don
>> > > >>>> >>>
>> > > >>>> >>> --
>> > > >>>> >>> Don MacQueen
>> > > >>>> >>> Lawrence Livermore National Laboratory
>> > > >>>> >>> 7000 East Ave., L-627
>> > > >>>> >>> Livermore, CA 94550
>> > > >>>> >>> 925-423-1062
>> > > >>>> >>> Lab cell 925-724-7509
>> > > >>>> >>>
>> > > >>>> >>>
>> > > >>>> >>>
>> > > >>>> >>> On 7/30/18, 4:03 PM, "R-help on behalf of Jim Lemon"
>> > > >>>> >>> <r-help-bounces using r-project.org on behalf of
>> > > >drjimlemon using gmail.com>
>> > > >>>> >>> wrote:
>> > > >>>> >>>
>> > > >>>> >>> Hi Diego,
>> > > >>>> >>> You may have to do some conversion as you have three
>> > > >>>> >>> fields
>> > > >in
>> > > >>>> >>> the
>> > > >>>> >>> first line using the default space separator and five
>> > > >fields in
>> > > >>>> >>> subsequent lines. If the first line doesn't contain any
>> > > >important
>> > > >>>> >>> data
>> > > >>>> >>> you can just delete it or replace it with a meaningful
>> > > >header
>> > > >>>> >>> line
>> > > >>>> >>> with five fields and save the file under another name.
>> > > >>>> >>>
>> > > >>>> >>> It looks as thought you have date-time as two fields. If
>> > > >so, you
>> > > >>>> >>> can
>> > > >>>> >>> just read the first field if you only want the date:
>> > > >>>> >>>
>> > > >>>> >>> # assume you have removed the first line
>> > > >>>> >>> dadf<-read.table("xxx.txt",stringsAsFactors=FALSE
>> > > >>>> >>> dadf$date<-as.Date(dadf$V1,format="%Y-%m-%d")
>> > > >>>> >>>
>> > > >>>> >>> If you want the date/time:
>> > > >>>> >>>
>> > > >>>> >>>
>> > > >dadf$datetime<-strptime(paste(dadf$V1,dadf$V2),format="%Y-%m-%d
>> > > >>>> >>> %H:%M:%S")
>> > > >>>> >>>
>> > > >>>> >>> Jim
>> > > >>>> >>>
>> > > >>>> >>> On Tue, Jul 31, 2018 at 12:29 AM, Diego Avesani
>> > > >>>> >>> <diego.avesani using gmail.com> wrote:
>> > > >>>> >>> > Dear all,
>> > > >>>> >>> >
>> > > >>>> >>> > I am dealing with the reading of a *.txt file.
>> > > >>>> >>> > The txt file the following shape:
>> > > >>>> >>> >
>> > > >>>> >>> > 103001930 103001580 103001530
>> > > >>>> >>> > 1998-10-01 00:00:00 0.6 0 0
>> > > >>>> >>> > 1998-10-01 01:00:00 0.2 0.2 0.2
>> > > >>>> >>> > 1998-10-01 02:00:00 0.6 0.2 0.4
>> > > >>>> >>> > 1998-10-01 03:00:00 0 0 0.6
>> > > >>>> >>> > 1998-10-01 04:00:00 0 0 0
>> > > >>>> >>> > 1998-10-01 05:00:00 0 0 0
>> > > >>>> >>> > 1998-10-01 06:00:00 0 0 0
>> > > >>>> >>> > 1998-10-01 07:00:00 0.2 0 0
>> > > >>>> >>> >
>> > > >>>> >>> > If it is possible I have a coupe of questions, which
>> > > >>>> >>> will
>> > > >sound
>> > > >>>> >>> stupid but
>> > > >>>> >>> > they are important to me in order to understand ho R
>> > > >>>> >>> deal
>> > > >with
>> > > >>>> >>> file
>> > > >>>> >>> or date.
>> > > >>>> >>> >
>> > > >>>> >>> > 1) Do I have to convert it to a *csv file?
>> > > >>>> >>> > 2) Can a deal with space and not ","
>> > > >>>> >>> > 3) How can I read date?
>> > > >>>> >>> >
>> > > >>>> >>> > thanks a lot to all of you,
>> > > >>>> >>> > Thanks
>> > > >>>> >>> >
>> > > >>>> >>> >
>> > > >>>> >>> > Diego
>> > > >>>> >>> >
>> > > >>>> >>> > [[alternative HTML version deleted]]
>> > > >>>> >>> >
>> > > >>>> >>> > ______________________________________________
>> > > >>>> >>> > R-help using r-project.org mailing list -- To UNSUBSCRIBE
>> and
>> > > >more,
>> > > >>>> >>> see
>> > > >>>> >>> > https://stat.ethz.ch/mailman/listinfo/r-help
>> > > >>>> >>> > PLEASE do read the posting guide
>> > > >>>> >>> http://www.R-project.org/posting-guide.html
>> > > >>>> >>> > and provide commented, minimal, self-contained,
>> > > >reproducible
>> > > >>>> >>> code.
>> > > >>>> >>>
>> > > >>>> >>> ______________________________________________
>> > > >>>> >>> R-help using r-project.org mailing list -- To UNSUBSCRIBE and
>> > > >more, see
>> > > >>>> >>> https://stat.ethz.ch/mailman/listinfo/r-help
>> > > >>>> >>> PLEASE do read the posting guide
>> > > >>>> >>> http://www.R-project.org/posting-guide.html
>> > > >>>> >>> and provide commented, minimal, self-contained,
>> > > >reproducible
>> > > >>>> >>> code.
>> > > >>>> >>>
>> > > >>>> >>>
>> > > >>>> >>
>> > > >>>> >
>> > > >>>
>> > > >>>
>> > > >>
>> > > >
>> > > >______________________________________________
>> > > >R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> > > >https://stat.ethz.ch/mailman/listinfo/r-help
>> > > >PLEASE do read the posting guide
>> > > >http://www.R-project.org/posting-guide.html
>> > > >and provide commented, minimal, self-contained, reproducible code.
>> > >
>> > > --
>> > > Sent from my phone. Please excuse my brevity.
>> > >
>> >
>> > [[alternative HTML version deleted]]
>> >
>> > ______________________________________________
>> > R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> > https://stat.ethz.ch/mailman/listinfo/r-help
>> > PLEASE do read the posting guide http://www.R-project.org/posti
>> ng-guide.html
>> > and provide commented, minimal, self-contained, reproducible code.
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