[R] help with merging two dataframes function of "egrep"-like formulas

[Bogdan Tanasa]

it looks great, thank you very much Jeff for your time and kind help !

On Wed, Jul 18, 2018 at 7:51 PM, Jeff Newmiller <jdnewmil using dcn.davis.ca.us>
wrote:

> The traditional (SQL) way to attack this problem is to make the data
> structure simpler so that faster comparisons can be utilized:
>
> ################
> A <- data.frame(z=c("a*b", "c*d", "d*e", "e*f"), t =c(1, 2, 3, 4))
> B <- data.frame(z=c("a*b::x*y", "c", "", "g*h"), t =c(1, 2, 3, 4))
>
> library(dplyr)
> #>
> #> Attaching package: 'dplyr'
> #> The following objects are masked from 'package:stats':
> #>
> #>     filter, lag
> #> The following objects are masked from 'package:base':
> #>
> #>     intersect, setdiff, setequal, union
> library(tidyr)
> Bx <- (   B
>       %>% mutate( z_B = as.character( z ) )
>       %>% rename( t_B = t )
>       %>% separate_rows( z, sep="::" )
>       )
> Bx
> #>     z t_B      z_B
> #> 1 a*b   1 a*b::x*y
> #> 2 x*y   1 a*b::x*y
> #> 3   c   2        c
> #> 4       3
> #> 5 g*h   4      g*h
> result <- (   A
>           %>% mutate( z = as.character( z ) )
>           %>% rename( t_A = t )
>           %>% inner_join( Bx, by="z" )
>           )
> result
> #>     z t_A t_B      z_B
> #> 1 a*b   1   1 a*b::x*y
>
> #' Created on 2018-07-18 by the [reprex package](http://reprex.tidyver
> se.org) (v0.2.0).
> ################
>
> Note that this is preferable if you can avoid ever creating the complex
> data z in B, but Bx is much more flexible and less error prone than B.
> (Especially if you don't have to create B$z_B at all, but have some other
> unique identifier(s) for the groupings represented by each row in B.)
>
>
> On Wed, 18 Jul 2018, Bogdan Tanasa wrote:
>
> Thanks a lot ! It looks that I am getting the same results with :
>>
>> B %>% regex_left_join(A, by = c(z = 'z'))
>>
>> On Wed, Jul 18, 2018 at 3:57 PM, Riley Finn <rileyfinn3 using gmail.com> wrote:
>>
>> please may I ask for a piece of advise regarding merging two dataframes :
>>>
>>>> A <- data.frame(z=c("a*b", "c*d", "d*e", "e*f"), t =c(1, 2, 3, 4))
>>>> B <- data.frame(z=c("a*b::x*y", "c", "", "g*h"), t =c(1, 2, 3, 4))
>>>> function of the criteria :
>>>> if "the elements in the 1st column of A could be found among the
>>>> elements
>>>> of the 1st column of B" i.e.
>>>> for the example above, we shall combine in the results only the row with
>>>> "a*b" of A with the row with "a*b::x*y" of B.
>>>>
>>>
>>>
>>> This may be what you are looking for:
>>>
>>> library(fuzzyjoin)
>>>
>>> The inner join returns just the one row where the string matches.
>>> B %>%
>>>   regex_inner_join(A, by = c(z = 'z'))
>>>
>>> While the full join returns NA's where the string does not match.
>>> B %>%
>>>   regex_full_join(A, by = c(z = 'z'))
>>>
>>> On Wed, Jul 18, 2018 at 5:20 PM Bogdan Tanasa <tanasa using gmail.com> wrote:
>>>
>>> Dear all,
>>>>
>>>> please may I ask for a piece of advise regarding merging two dataframes
>>>> :
>>>>
>>>> A <- data.frame(z=c("a*b", "c*d", "d*e", "e*f"), t =c(1, 2, 3, 4))
>>>>
>>>> B <- data.frame(z=c("a*b::x*y", "c", "", "g*h"), t =c(1, 2, 3, 4))
>>>>
>>>> function of the criteria :
>>>>
>>>> if "the elements in the 1st column of A could be found among the
>>>> elements
>>>> of the 1st column of B" i.e.
>>>>
>>>> for the example above, we shall combine in the results only the row with
>>>> "a*b" of A with the row with "a*b::x*y" of B.
>>>>
>>>> thank you,
>>>>
>>>> bogdan
>>>>
>>>>         [[alternative HTML version deleted]]
>>>>
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>>>> posting-guide.html
>>>> and provide commented, minimal, self-contained, reproducible code.
>>>>
>>>>
>>>
>>         [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posti
>> ng-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
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