[R] Storing tableGrobs in a list

Jeff Newmiller jdnewm|| @end|ng |rom dcn@d@v|@@c@@u@
Fri Jun 15 03:30:33 CEST 2018


I don't know gtable_combine well enough to answer based on hand waving. A reproducible example is more likely to tempt someone to dig a little.

On June 14, 2018 8:07:19 AM HST, Stats Student <stats.student4647 using gmail.com> wrote:
>Thanks for the replies. Wasn't aware that Gmail on Android sent HTML by
>default, apologies.
>
>Storing the tableGrob-s in a list worked but for some reason
>grid.arrange complains on output from gtable_combine() using lists vs
>individual tableGrob-s.
>
># works when supplying individual tableGrobs
>
>p1<-gtable_combine(p11,p22, along=2)
>p2<-gtable_combine(p11,p22, along=2)
>grid.arrange(p1,p2,ncol=2)
>
># breaks when supplying a list of tableGrobs, error from grid.arrange()
>
>p1<-gtable_combine(L1,along=2)
>p2<-gtable_combine(L2,along=2)
>
>grid.arrange(p1,p2,ncol=2)
>
>Error in gList(list(list(grobs = list(list(label = "status", x = 0.5, 
>: 
>  only 'grobs' allowed in "gList"
>
>Also tried, still no go
>
>p1<-do.call(gtable_combine, list(L1,along=2))
>p2<-do.call(gtable_combine, list(L2,along=2))
>
>
>
>
>On Jun 13, 2018, 11:01 PM, at 11:01 PM, Jeff Newmiller
><jdnewmil using dcn.davis.ca.us> wrote:
>>?`[[`
>>
>>and read the discussions of indexing in the Introduction to R document
>>that comes with R. Also, find a way to predict the number of elements
>>you will need as making this a habit will pay off big time when you
>>work with large amounts of data:
>>
>>L1<-vector( "list", N )
>>for (i in seq.int( N )) {
>>   L1[[i]] <-tableGrob( ... )
>>}
>>
>>PS Post using your email program "plain text" mode... HTML gets
>>stripped anyway and that often leads to partial corruption of your
>>message. Read the Posting Guide.
>>
>>On June 13, 2018 4:43:21 PM HST, Stats Student
>><stats.student4647 using gmail.com> wrote:
>>>Hi, I'm trying to generate tableGrobs in a loop, store them in a list
>>>so I
>>>can use it in a call to gtable_combine().
>>>
>>>L1<-list()
>>>for (i in seq( ... )) {
>>>   L1[i] <-tableGrob( ... )
>>>}
>>>
>>>gtable_combine(L1, along=1)
>>>
>>>On the assignment inside the loop, I get "number of items to replace
>>is
>>>not
>>>a multiple of replacement length" which I'm guessing has to do with
>>the
>>>tableGrob object not "fitting" in the list but am not sure how to fix
>>>it.
>>>
>>>Thanks in advance for any pointers.
>>>
>>>	[[alternative HTML version deleted]]
>>>
>>>______________________________________________
>>>R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
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>>>PLEASE do read the posting guide
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>>>and provide commented, minimal, self-contained, reproducible code.
>>
>>--
>>Sent from my phone. Please excuse my brevity.

-- 
Sent from my phone. Please excuse my brevity.




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