[R] Mean of a row of a data frame

[Richard M. Heiberger]

> mean(list(1,4,0))
[1] NA
Warning message:
In mean.default(list(1, 4, 0)) :
  argument is not numeric or logical: returning NA
> mean(unlist(roop[1,]))
[1] 1.666667
> apply(roop, 1, mean)
[1] 1.666667 5.333333 3.000000

data.frame is a list with some matrix characteristics.
The list characteristics are winning in this example.

Look at the definition of apply.   It has an as.matrix in it that
removes the list behavior.

Rich


On Tue, Mar 20, 2018 at 10:18 PM, Sorkin, John
<jsorkin at som.umaryland.edu> wrote:
> I am trying to get the mean of a row of a data frame. My code follows:
>
>
> roop <- data.frame(x=c(1,2,3),y=c(4,5,2),z=c(0,9,4))
> roop
> mean(roop[1,])
> mean(roop[1,c("x","y","z")])
>
>
> I get the following output:
>
>> roop
>   x y z
> 1 1 4 0
> 2 2 5 9
> 3 3 2 4
>> mean(roop[1,])
> [1] NA
> Warning message:
> In mean.default(roop[1, ]) :
>   argument is not numeric or logical: returning NA
>> mean(roop[1,c("x","y","z")])
> [1] NA
> Warning message:
> In mean.default(roop[1, c("x", "y", "z")]) :
>   argument is not numeric or logical: returning NA
>
>
> It is clear the the mean function does not like the data I am passing to it. I do not know why. How might I correct my code?
>
>
> As always,
>
> Thank you,
>
> John
>
>
> Thank you,
>
> John
>
>
>
>
>
> John David Sorkin M.D., Ph.D.
> Professor of Medicine
> Chief, Biostatistics and Informatics
> University of Maryland School of Medicine Division of Gerontology and Geriatric Medicine
> Baltimore VA Medical Center
> 10 North Greene Street
> GRECC (BT/18/GR)
> Baltimore, MD 21201-1524
> (Phone) 410-605-7119
> (Fax) 410-605-7913 (Please call phone number above prior to faxing)
>
>
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