[R] Remove specific rows from nested list of matrices

[Ek Esawi]

Thank you Jeff and Bert. I know i have to use dput add  provide a
reproducible example. The problem is that the output,is huge, has many
nested lists, and the info is private.

Here is the first line of dput(FF) if it helps:
dput(FF)
list(list(list(structure(c("12/30 12/30", "01/02 01/02", "01/02 01/02",

Thanks again--EK
On Fri, Nov 2, 2018 at 11:21 AM Jeff Newmiller <jdnewmil using dcn.davis.ca.us> wrote:
>
> Can you supply the output of
>
> dput(FF)
>
> ?
>
> On November 2, 2018 8:00:08 AM PDT, Ek Esawi <esawiek using gmail.com> wrote:
> >Hi All,
> >
> >I have a list that is made up of nested lists, as shown below. I want
> >to remove all rows in each sub-list that start with an empty space,
> >that’s the first entry of a row is blank; for example, on
> >[[1]][[1]][[1]] Remove row 4,on [[1]][[1]][[3]] remove row 5, on
> >[[1]][[2]][[1]] remove row 6, etc.. All rows start with 2 digits/ 2
> >digits. My formula works on individual sublist but not the whole
> >list.. I know my indexing is wrong, but don’t know how to fix it.
> >
> >
> >> FF
> >
> >[[1]]
> >[[1]][[1]]
> >[[1]][[1]][[1]]
> >[,1]    [,2]   [,3]    [,4] [,5]
> >[1,] "30/20"   "AAAAAAAA" “    “   "-89"
> >[2,] "02/20"   "AAAAAAAA” “    “   "-98"
> >[3,] "02/20"   “AAAAAAA” “    “   "-84"
> >[4,] “  “ “  “   “
> >[[1]][[1]][[2]]
> >[,1]    [,2]
> >[1,] "02/23" “AAAAAAAA” : 29" “
> >[2,] "02/23" “AAAAAAAA” ." “
> >[3,] "02/23" “AAAAAAAA” " “
> >[4,] "02/23" “AAAAAAAA” "
> >[[1]][[1]][[3]]
> >[,1]    [,2]    [,3] [,4] [,5] [,6] [,7]
> >[1,] "01/09" “AAAAAAAA"    “   “   “   "53"
> >[2,] "01/09" “AAAAAAAA” "   “   “   “   "403"
> >[3,] "01/09" “AAAAAAAA” "   “   “   “   "83"
> >[4,] "01/09" “AAAAAAAA” "   “   “   “   "783"
> >[5,] “  “  “AAAAAAAA”  3042742181"   “   “   “   “
> >[[1]][[2]]
> >[[1]][[2]][[1]]
> >[,1]  [,2] [,3] [,4] [,5]
> >[1,] “    “   “   “   “AAAAAAAA” "
> >[2,] "Standard Purchases"  “   “   “   "
> >[3,] "24/90 "AAAAAAAA” “   "243"  "
> >[4,] "24/90 "AAAAAAAA” "   "143"  "
> >[5,] "24/91 "AAAAAAAA” " “   "143" “
> >[6,] “    “   “   “   "792"
> >[[1]][[2]][[2]]
> >[,1]    [,2]
> >[1,] "02/23" “AAAAAAAA”: 31" “
> >[2,] "02/23" “AAAAAAAA”." “
> >[3,] "02/23" “AAAAAAAA” " “
> >[4,] "02/23" “AAAAAAAA”
> >[5,] "02/23" “AAAAAAAA”
> >[6,] "02/23" “AAAAAAAA” 20"
> >[7,] "02/23" “AAAAAAAA”  “
> >[8,] "02/23" “AAAAAAAA” "33"
> >[[1]][[3]]
> >[[1]][[3]][[1]]
> >[,1]    [,2]
> >[1,] "02/23" “AAAAAAAA”: 28" “
> >[2,] "02/23" “AAAAAAAA”." “
> >[3,] "02/23" “AAAAAAAA” " “
> >[4,] "02/23" “AAAAAAAA” "
> >[[1]][[3]][[2]]
> >[,1]    [,2]    [,3]    [,4] [,5] [,6] [,7]    [,8]    [,9]
> >[1,] "02/23" “AAAAAAAA” " “   “   "53" "
> >[2,] "02/24" “AAAAAAAA” " “   “   "
> >[3,] “  “  “  “   “   “   “  “  "1,241"
> >[4,] "02/24" "AAAAAAAA”  “   "33”
> >
> >My Formula,:
> >
> >G <- lapply(FF, function(x) lapply(x, function (y) lapply(y,
> >function(z)  z[grepl("^[0-9][0-9]/",z[,1]),])))
> >
> >The error: Error in z[, 1] : incorrect number of dimensions
> >
> >
> >
> >Thanks in advance--EK
> >
> >______________________________________________
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> >and provide commented, minimal, self-contained, reproducible code.
>
> --
> Sent from my phone. Please excuse my brevity.