[R] Sum of Squares Type I, II, III for ANOVA

Fox, John jfox @ending from mcm@@ter@c@
Wed Nov 7 03:41:20 CET 2018


Dear Thanh Tran,

When you start a discussion on r-help, it's polite to keep it there so other people can see what transpires. I'm consequently cc'ing this response to the r-help list.

The problem with your code is that anova(), as opposed to Anova(), has no type argument.

Here's what I get with your data. I hope that the code and output don't get too mangled:

> data <- read.csv("Saha research.csv", header=TRUE)

> data <- within(data, {
+     tem <- as.factor(temperature)
+     ac <- as.factor (AC)
+     av <- as.factor(AV)
+     thick <- as.factor(Thickness)
+ })

> library(car)
Loading required package: carData

> options(contrasts = c("contr.sum", "contr.poly"))

> mod <- lm(KIC ~ tem*ac + tem*av + tem*thick + ac*av +ac*thick + av*thick, 
+           data=data)

> anova(mod) # type I (sequential)
Analysis of Variance Table

Response: KIC
           Df  Sum Sq Mean Sq  F value    Pr(>F)    
tem         2 15.3917  7.6958 427.9926 < 2.2e-16 ***
ac          2  0.1709  0.0854   4.7510 0.0096967 ** 
av          1  1.9097  1.9097 106.2055 < 2.2e-16 ***
thick       2  0.2041  0.1021   5.6756 0.0040359 ** 
tem:ac      4  0.5653  0.1413   7.8598 6.973e-06 ***
tem:av      2  1.7192  0.8596  47.8046 < 2.2e-16 ***
tem:thick   4  0.0728  0.0182   1.0120 0.4024210    
ac:av       2  0.3175  0.1588   8.8297 0.0002154 ***
ac:thick    4  0.0883  0.0221   1.2280 0.3003570    
av:thick    2  0.0662  0.0331   1.8421 0.1613058    
Residuals 190  3.4164  0.0180                       
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

> Anova(mod) # type II
Anova Table (Type II tests)

Response: KIC
           Sum Sq  Df  F value    Pr(>F)    
tem       15.3917   2 427.9926 < 2.2e-16 ***
ac         0.1709   2   4.7510 0.0096967 ** 
av         1.9097   1 106.2055 < 2.2e-16 ***
thick      0.2041   2   5.6756 0.0040359 ** 
tem:ac     0.5653   4   7.8598 6.973e-06 ***
tem:av     1.7192   2  47.8046 < 2.2e-16 ***
tem:thick  0.0728   4   1.0120 0.4024210    
ac:av      0.3175   2   8.8297 0.0002154 ***
ac:thick   0.0883   4   1.2280 0.3003570    
av:thick   0.0662   2   1.8421 0.1613058    
Residuals  3.4164 190                       
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

> Anova(mod, type=3) # type III
Anova Table (Type III tests)

Response: KIC
             Sum Sq  Df   F value    Pr(>F)    
(Intercept) 102.430   1 5696.4740 < 2.2e-16 ***
tem          15.392   2  427.9926 < 2.2e-16 ***
ac            0.171   2    4.7510 0.0096967 ** 
av            1.910   1  106.2055 < 2.2e-16 ***
thick         0.204   2    5.6756 0.0040359 ** 
tem:ac        0.565   4    7.8598 6.973e-06 ***
tem:av        1.719   2   47.8046 < 2.2e-16 ***
tem:thick     0.073   4    1.0120 0.4024210    
ac:av         0.318   2    8.8297 0.0002154 ***
ac:thick      0.088   4    1.2280 0.3003570    
av:thick      0.066   2    1.8421 0.1613058    
Residuals     3.416 190                        
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

If you have questions about Minitab there's probably another place to ask. It's not my opinion that type-III tests are generally preferable to type-II tests. Focus, in my opinion, should be on what hypotheses are being tested. If you want to see more detail, you could consult the book with which the car package is associated: see citation(package="car").

Best,
 John

> -----Original Message-----
> From: Thanh Tran [mailto:masternhattt using gmail.com]
> Sent: Tuesday, November 6, 2018 9:15 PM
> To: Fox, John <jfox using mcmaster.ca>
> Subject: Re: [R] Sum of Squares Type I, II, III for ANOVA
> 
> Dear  Prof. John Fox,
> Thank you for your answer. The CSV data was added as the attached file again.
> I try to set the contrasts properly *before* I fit the model but I received a
> problem as follows.
> 
> >  setwd("C:/NHAT/HOC TAP/R/Test/Anova") data = read.csv("Saha
> > research.csv", header =T)
> > attach(data)
> > tem = as.factor(temperature)
> > ac= as.factor (AC)
> >  av = as.factor(AV)
> >  thick = as.factor(Thickness)
> > library(car)
> Loading required package: carData
> > options(contrasts = c("contr.sum", "contr.poly")) mod <- lm(KIC ~
> > tem*ac + tem*av + tem*thick + ac*av +ac*thick + av*thick)
> > anova(mod,type= 3)
> Error: $ operator is invalid for atomic vectors
> 
> 
> Another problem is that in the paper that I read, the authors used MINITAB to
> analyze Anova. The authors use "adjusted sums of squares" calculate the p-
> value. So which should I use? Type I adjusted SS or Type III sequential SS?
> Minitab help tells me that I would "usually" want to use type III adjusted SS, as
> type I sequential "sums of squares can differ when your design is unbalanced"
> - which mine is. The R functions I am using are clearly using the type I
> sequential SS.
> 
> Thanks
> Nhat Tran
> 
> 
> Vào Th 4, 7 thg 11, 2018 vào lúc 10:41 Fox, John <jfox using mcmaster.ca
> <mailto:jfox using mcmaster.ca> > đã viết:
> 
> 
> 	Dear Nhat Tran,
> 
> 	The output that you show is unreadable and as far as I can see, the
> data aren't attached, but perhaps the following will help: First, if you want
> Anova() to compute type III tests, then you have to set the contrasts properly
> *before* you fit the model, not after. Second, you can specify the model much
> more compactly as
> 
> 	  mod <- lm(KIC ~ tem*ac + tem*av + tem*thick + ac*av +ac*thick +
> av*thick)
> 
> 	Finally, as sound general practice, I'd not attach the data, but rather
> put your recoded variables in the data frame and then specify the data
> argument to lm().
> 
> 	I hope that this helps,
> 	 John
> 
> 	-----------------------------------------------------------------
> 	John Fox
> 	Professor Emeritus
> 	McMaster University
> 	Hamilton, Ontario, Canada
> 	Web: https://socialsciences.mcmaster.ca/jfox/
> 
> 
> 
> 	> -----Original Message-----
> 	> From: R-help [mailto:r-help-bounces using r-project.org <mailto:r-help-
> bounces using r-project.org> ] On Behalf Of Thanh Tran
> 	> Sent: Tuesday, November 6, 2018 6:58 PM
> 	> To: r-help using r-project.org <mailto:r-help using r-project.org>
> 	> Subject: [R] Sum of Squares Type I, II, III for ANOVA
> 	>
> 	> Hi everyone,
> 	> I'm studying the ANOVA in R and have some questions to share. I
> investigate
> 	> the effects of 4 factors (temperature-3 levels, asphalt content-3
> levels, air
> 	> voids-2 levels, and sample thickness-3 levels) on the hardness of
> asphalt
> 	> concrete in the tensile test (abbreviated as KIC). These data were
> taken from a
> 	> acticle paper. The codes were wrriten as the follows:
> 	>
> 	> > data = read.csv("Saha research.csv", header =T)
> 	> > attach(data)
> 	> > tem = as.factor(temperature)
> 	> > ac= as.factor (AC)
> 	> > av = as.factor(AV)
> 	> > thick = as.factor(Thickness)
> 	> > model =
> 	>
> lm(KIC~tem+ac+av+thick+tem:ac+tem:av+tem:thick+ac:av+ac:thick+av:thick)
> 	> > anova(model) #Type I tests
> 	> > library(car) Loading required package: carData >
> 	>
> anova(lm(KIC~tem+ac+av+thick+tem:ac+tem:av+tem:thick+ac:av+ac:thick+av
> 	> :thick),type=2)
> 	> Error: $ operator is invalid for atomic vectors
> 	> > options(contrasts = c("contr.sum", "contr.poly"))
> 	> > Anova(model,type="3") # Type III tests
> 	> > Anova(model,type="2") # Type II tests
> 	>
> 	> With R, three results from Type I, II, and III almost have the same as
> follows.
> 	>
> 	> Analysis of Variance Table Response: KIC Df Sum Sq Mean Sq F value
> Pr(>F)
> 	> tem 2 15.3917 7.6958 427.9926 < 2.2e-16 *** ac 2 0.1709 0.0854
> 4.7510
> 	> 0.0096967 ** av 1 1.9097 1.9097 106.2055 < 2.2e-16 *** thick 2
> 0.2041
> 	> 0.1021 5.6756 0.0040359 ** tem:ac 4 0.5653 0.1413 7.8598 6.973e-
> 06 ***
> 	> tem:av 2 1.7192 0.8596 47.8046 < 2.2e-16 *** tem:thick 4 0.0728
> 0.0182
> 	> 1.0120 0.4024210 ac:av 2 0.3175 0.1588 8.8297 0.0002154 ***
> ac:thick 4
> 	> 0.0883 0.0221 1.2280 0.3003570 av:thick 2 0.0662 0.0331 1.8421
> 0.1613058
> 	> Residuals 190 3.4164 0.0180 --- Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01
> ‘*’
> 	> 0.05 ‘.’ 0.1 ‘ ’ 1
> 	>
> 	> However, these results are different from the results in the article,
> especially
> 	> for the interaction (air voids and sample thickness). The results
> presented in
> 	> the article are as follows:
> 	> Analysis of variance for KIC, using Adjusted SS for tests. Source DF
> Seq SS Adj
> 	> MS F-stat P-value Model findings Temperature 2 15.39355 7.69677
> 426.68
> 	> <0.01 Significant AC 2 0.95784 0.47892 26.55 <0.01 Significant AV 1
> 0.57035
> 	> 0.57035 31.62 <0.01 Significant Thickness 2 0.20269 0.10135 5.62
> <0.01
> 	> Significant Temperature⁄AC 4 1.37762 0.34441 19.09 <0.01
> Significant
> 	> Temperature⁄AV 2 0.8329 0.41645 23.09 <0.01 Significant
> 	> Temperature⁄thickness 4 0.07135 0.01784 0.99 0.415 Not
> significant AC⁄AV 2
> 	> 0.86557 0.43279 23.99 <0.01 Significant AC⁄thickness 4 0.04337
> 0.01084 0.6
> 	> 0.662 Not significant AV⁄thickness 2 0.17394 0.08697 4.82 <0.01
> Significant
> 	> Error 190 3.42734 0.01804 Total 215 23.91653
> 	>
> 	> Therefore, I wonder that whether there is an error in my code or
> there is
> 	> another type of ANOVA in R. If you could answer my problems, I
> would be
> 	> most grateful.
> 	> Best regards,
> 	> Nhat Tran
> 	> Ps: I also added a CSV file and the paper for practicing R.
> 	> ______________________________________________
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