[R] date

Bert Gunter bgunter@4567 @end|ng |rom gm@||@com
Thu Dec 19 13:30:07 CET 2019


"But the important point is:
If you know the structure of the data you want to
parse, then it is best to tell R (or any other language)
this structure explicitly. "

Fortune nomination!

-- Bert






Thu, Dec 19, 2019, 2:49 AM Enrico Schumann <es using enricoschumann.net> wrote:

>
> Quoting Eric Berger <ericjberger using gmail.com>:
>
> > Martin  writes: "there's really no reason for going beyond base R"
> >
> > I disagree. Lubridate is a fantastic package. I use it all the time. It
> > makes working with dates really easy, as evidenced by John Kane's
> > suggestion. I strongly recommend learning to work with it.
> >
> > The bottom line: as is often the case, there are many different ways to
> > accomplish a task in R.
>
> I apologise beforehand if this sparks an unnecessary discussion ;-)
>
> But the important point is:
> If you know the structure of the data you want to
> parse, then it is best to tell R (or any other language)
> this structure explicitly.
>
>
> > On Thu, Dec 19, 2019 at 10:31 AM Martin Maechler <
> maechler using stat.math.ethz.ch>
> > wrote:
> >
> >> >>>>> John Kane
> >> >>>>>     on Tue, 17 Dec 2019 20:28:17 -0500 writes:
> >>
> >>     > library(lubridate)
> >>     > gs$dat1  <-  mdy(gs$date)
> >>
> >> there's really no reason for going beyond base R.
> >>
> >> Using the proper format as per Patrick and Peter's advice
> >> (below) is perfectly clear and actually
> >> more robust (for the next data set etc)
> >> than going via "good guessing" in extra packages.
> >>
> >>     > On Tue, 17 Dec 2019 at 18:38, peter dalgaard <pdalgd using gmail.com>
> >> wrote:
> >>     >>
> >>     >> ...and switch the order, and use %y for 2-digit years.
> >>     >>
> >>     >> > On 17 Dec 2019, at 23:57 , Patrick (Malone Quantitative) <
> >> malone using malonequantitative.com> wrote:
> >>     >> >
> >>     >> > Try putting / instead of - in your format, to match the data.
> >>     >> >
> >>     >> > On Tue, Dec 17, 2019 at 5:52 PM Val <valkremk using gmail.com>
> wrote:
> >>     >> >>
> >>     >> >> Hi All,
> >>     >> >>
> >>     >> >> I wanted to to convert character date  mm/dd/yy  to YYYY-mm-dd
> >>     >> >> The sample data and my attempt is shown below
> >>     >> >>
> >>     >> >> gs <-read.table(text="ID date
> >>     >> >> A1   09/27/03
> >>     >> >> A2   05/27/16
> >>     >> >> A3   01/25/13
> >>     >> >> A4   09/27/19",header=TRUE,stringsAsFactors=F)
> >>     >> >>
> >>     >> >> Desired output
> >>     >> >>  ID     date      d1
> >>     >> >> A1 09/27/03 2003-09-27
> >>     >> >> A2 05/27/16 2016-05-27
> >>     >> >> A3 01/25/13 2012-04-25
> >>     >> >> A4 09/27/19 2019-09-27
> >>     >> >>
> >>     >> >> I used this
> >>     >> >> gs$d1 = as.Date(as.character(gs$date), format = "%Y-%m-%d")
> >>     >> >>
> >>     >> >> but I got NA's.
> >>     >> >>
> >>     >> >> How do I get my desired result?
> >>     >> >> Thank you.
> >>     >> >>
> >>     >>
> >>     >> --
> >>     >> Peter Dalgaard, Professor,
> >>     >> Center for Statistics, Copenhagen Business School
> >>     >> Solbjerg Plads 3, 2000 Frederiksberg, Denmark
> >>     >> Phone: (+45)38153501
> >>     >> Office: A 4.23
> >>     >> Email: pd.mes using cbs.dk  Priv: PDalgd using gmail.com
> >>     >>
> >>
> >>     > --
> >>     > John Kane
> >>     > Kingston ON Canada
>
>
>
> --
> Enrico Schumann
> Lucerne, Switzerland
> http://enricoschumann.net
>
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