[R] troubleshooting data structure to run krippendorff's alpha

Jim Lemon drj|m|emon @end|ng |rom gm@||@com
Mon Jan 28 10:36:13 CET 2019


Hi Halllie,
As Jeff noted, a data frame is not a matrix (it is a variety of list),
so that looks like your problem.

hkdf<-data.frame(sample(3:5,4,TRUE),sample(1:3,4,TRUE),sample(2:4,4,TRUE),
 sample(3:5,4,TRUE),sample(1:3,4,TRUE),sample(2:4,4,TRUE))
library(irr)
kripp.alpha(hkdf)
kripp.alpha(as.matrix(hkdf))

Jim

On Mon, Jan 28, 2019 at 6:04 PM Hallie Kamesch <hallie.kamesch using gmail.com> wrote:
>
> Hi -
> I'm trying to run Krippendorff's alpha for data consisting of 4 subjects
> rated on 6 events each by three raters.  The ratings are interval ratio
> scale data.
>
> I've rearranged my data into a 3 x 24  of ratersXevents. (per this
> discussion on CrossValidated: (
> https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144)
> ).
>
> This is the code I've used:
> library(irr)
> dat <- read.csv(file.choose(), header = TRUE)
> head(dat)
> kripp.alpha(dat, method=c("ratio"))
> #### error message: Error in sort.list(y) : 'x' must be atomic for
> 'sort.list'
> Have you called 'sort' on a list?
> kripp.alpha(dat,"ratio")
> #### error message: Error in sort.list(y) : 'x' must be atomic for
> 'sort.list'
> Have you called 'sort' on a list?
>
> I read rhelp on sort, but I'm still confused.  Please help!
> Thank you!
>
> PS
> I arranged my data in that matrix based upon this comment and response from
> the CrossValidated posting forum (
> https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144),
> but my question above was rejected there.
>
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>
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