[R] create a r list from dataframe using the first column as list names
bgunter@4567 @end|ng |rom gm@||@com
Fri Apr 10 20:07:47 CEST 2020
"I thought: why make this overly complicated,..."
Indeed, though "complicated" is in the eyes of the beholder.
One wonders whether any of this is necessary, though: see ?apply , as in
apply(a, 1, whatever...)
to do things rowwise.
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Fri, Apr 10, 2020 at 9:14 AM Rasmus Liland <jensrasmus using gmail.com> wrote:
> On 2020-04-09 18:00 +0000, aiguo li wrote:
> | That is awesome! Thanks.
> Dear AiGuo,
> I thought: why make this overly
> complicated, when this is also
> a <- matrix(LETTERS[1:16], nrow=4)
> X <- split(x=a[,-1], f=a[,1])
> lapply(X=X, FUN=as.factor)
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> and provide commented, minimal, self-contained, reproducible code.
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