[R] replace zero in a matrix using random numbers

[Bert Gunter]

?rnorm tells you that n, the first argument, is the number of
observations/random numbers you wish to generate. You asked for 1.
So you need to ask for the number of 0's, something like:

> a <- matrix(rep(0:1, 3), nrow =3)
> a
     [,1] [,2]
[1,]    0    1
[2,]    1    0
[3,]    0    1
> a[!a] <- rnorm(sum(!a), 1,.1)
> a
          [,1]     [,2]
[1,] 0.8136788 1.000000
[2,] 1.0000000 1.146225
[3,] 0.9081908 1.000000

Bert


Bert Gunter

"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )


On Fri, Jan 8, 2021 at 2:33 PM Yuan Chun Ding <ycding using coh.org> wrote:

> Hi R users,
>
> I am analyzing miRNA sequence data for a special network analysis, I need
> to replace zero values in a matrix as random numbers with mean of 1 and
> standard deviation of 0.1.
>
> er.miRCounts[er.miRCounts==0] <- rnorm(1,mean=1, sd=0.1);
>
> this code made all zero values as 1.13, not random numbers across
> different zero values.  If all zero values in one row are replaced by the
> same 1.13,  then sd in that row is zero, causing other problem in the
> following calculation.
>
> Can you help me?
>
> Thank you,
>
> Yuan chun Ding
>
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