[R] Help with Krippendorff's Alpha

[Bert Gunter]

Well,....

"Appreciate the help!"

Indeed, you should for any that you receive. But do note per the posting
guide linked below:

"For questions about functions in standard packages distributed with R (see
the FAQ Add-on packages in R
<http://cran.r-project.org/doc/FAQ/R-FAQ.html#Add-on-packages-in-R>), ask
questions on R-help.
If the question relates to a *contributed package* , e.g., one downloaded
from CRAN, try contacting the package maintainer first. You can also use
find("functionname") and packageDescription("packagename") to find this
information. *Only* send such questions to R-help or R-devel if you get no
reply or need further assistance. This applies to both requests for help
and to bug reports."

So while optimism is often a virtue, don't be disappointed if it is not
rewarded here. For context, there are in excess of 20,000 R packages out
there, so expectations of help on any of them is a long shot.

Bert Gunter

"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )


On Fri, Jan 22, 2021 at 3:24 PM Jenn Russell <jenncami using hotmail.com> wrote:

> Hello!
>
> I am requesting help for a data set in which I have 6 evaluators (I've
> called them 'Trainers'), each of which took a questionnaire with 180
> questions. The possible answers to the questions are ordinal numbers. I am
> looking to test inter-rater reliability of the questionnaire using
> Krippendorff's alpha. I have already run this in R, however when I get the
> output it seems the matrix is inverted. While it seems like it should be an
> easy problem to fix I don't see how I would be able to create my matrix the
> other way without typing out all 180 scores manually. For reference, I'm
> using the irr package to use kripp.alpha().
>
> > Trainers<-matrix(c(Trainer_1,Trainer_2, Trainer_3, Trainer_5, Trainer_6,
> Trainer_12), ncol=6)
> > kripp.alpha(Trainers, method=c("ordinal"))
> Krippendorff's alpha
> Subjects = 6
> Raters = 180
> alpha = -0.00149
>
> While I'm getting an output - shouldn't my raters be 6 and my subjects be
> 180?
>
> Appreciate the help!
>
> JR
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

	[[alternative HTML version deleted]]