[R] Error in var(if (is.vector(x) || is.factor(x)) x else as.double(x), na.rm = na.rm)
Duncan Murdoch
murdoch@dunc@n @end|ng |rom gm@||@com
Sat Jun 26 10:45:45 CEST 2021
This is a duplicate of your SO post:
https://stackoverflow.com/questions/68135737/error-in-varif-is-vectorx-is-factorx-x-else-as-doublex
There you were asked for some data to make it reproducible. You
shouldn't assume that people here are any more clairvoyant than the SO
readers.
Duncan Murdoch
On 25/06/2021 2:54 p.m., Tariq Khasiri wrote:
> Just trying to replicate the Callaway and Sant'Anna average treatment
> group effect for my research where I would like to see how a particular law
> implementation is affecting all the treated states' wages compared to the
> never treated states' ( control group ) wage :
>
> ## Cleaning treated and never treated
>
> dat$treat = ifelse(is.na(dat$law_effective_year),0,1)
>
> dat$nevertreated = ifelse(dat$treat==0,1,0)
>
> ## Command for CSDID
>
> out1 <- att_gt(yname="ln_incwage",
> tname="year",
> gname="law_effective_year",
> xformla=~male + age + age2 + age3 + age4 + black + asian +
> hispanic + lths + hsdegree + somecollege ,
> data=dat,
> est_method = "dr", # "dr" is doubly robust. "ipw" is inverse
> probability weighting. "reg" is regression
> control_group = "nevertreated", # set the comparison group
> which is either "nevertreated" or "notyettreated"
> print_details = FALSE, # if TRUE, print detailed results
> clustervars = "statefip", # cluster level
> panel = FALSE) # wh)
>
> summary(out1)
>
> But the error I'm getting is -
>
> Error in var(if (is.vector(x) || is.factor(x)) x else as.double(x), na.rm =
> na.rm) :
> Calling var(x) on a factor x is defunct.
> Use something like 'all(duplicated(x)[-1L])' to test for a constant
> vector.
>
> Can anyone tell me what's the issue ?
>
> [[alternative HTML version deleted]]
>
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