[R] Problem with data distribution

Neha gupta neh@@bo|ogn@90 @end|ng |rom gm@||@com
Thu Feb 17 20:03:07 CET 2022


That is all the code I have. How can I provide a  reproducible code ?

How can I save this result?

On Thu, Feb 17, 2022 at 8:00 PM Ebert,Timothy Aaron <tebert using ufl.edu> wrote:

> You pipe the filter but do not save the result. A reproducible example
> might help.
> Tim
>
> -----Original Message-----
> From: R-help <r-help-bounces using r-project.org> On Behalf Of Neha gupta
> Sent: Thursday, February 17, 2022 1:55 PM
> To: r-help mailing list <r-help using r-project.org>
> Subject: [R] Problem with data distribution
>
> [External Email]
>
> Hello everyone
>
> I have a dataset with output variable "bug" having the following values
> (at the bottom of this email). My advisor asked me to provide data
> distribution of bugs with 0 values and bugs with more than 0 values.
>
> data = readARFF("synapse.arff")
> data2 = readARFF("synapse.arff")
> data$bug
> library(tidyverse)
> data %>%
>   filter(bug == 0)
> data2 %>%
>   filter(bug >= 1)
> boxplot(data2$bug, data$bug, range=0)
>
> But both the graphs are exactly the same, how is it possible? Where I am
> doing wrong?
>
>
> data$bug
>   [1] 0 1 0 0 0 1 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 2 0 0 0 0 1 0 0 0 0 0
> 0 4 1 0
>  [40] 0 1 0 0 0 0 0 0 1 0 3 2 0 0 0 0 3 0 0 0 0 2 0 0 0 1 0 0 0 0 1 1 1 0 0
> 0 0 0 0
>  [79] 1 1 2 1 0 1 0 0 0 2 2 1 1 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 5 0 0 0 0 0 0
> 7 0 0 1
> [118] 0 1 1 0 2 0 3 0 1 0 0 1 0 0 0 0 0 1 1 0 0 0 0 1 0 3 2 1 1 0 0 0 0 0 0
> 0 1 0 0
> [157] 0 0 0 0 0 0 0 0 0 1 0 1 0 0 3 0 0 1 0 1 3 0 0 0 0 0 0 0 0 1 0 4 1 1 0
> 0 0 0 1
> [196] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 0 1 0 0 0 0 0
>
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>
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