[R] Continuous variable into levels

Rui Barradas ru|pb@rr@d@@ @end|ng |rom @@po@pt
Fri Mar 4 00:06:39 CET 2022


Hello,

And ?findInterval is faster than hist.

findInterval(x, c(-Inf, 500, 1000, 5000))

Also, before the cut code, the OP wrote


if value is between 1-100 do something


but in the breaks vector there's no 100. I guess this is not important, 
though, only the function to bin the data is.

Hope this helps,

Rui Barradas

Às 22:38 de 03/03/2022, Jim Lemon escreveu:
> Sorry, it was such an easy question that I didn't even read it
> closely. Apparently using hist() is a bit faster. Whether this is
> worth it, I don't know.
> 
> Jim
> 
> On Fri, Mar 4, 2022 at 9:36 AM Neha gupta <neha.bologna90 using gmail.com> wrote:
>>
>> Hello Jim
>>
>> So, you believe the following way is better ?
>>
>> var2=cut(var1, br=c(-1,500, 501,1000, 1001,5000))
>>
>>
>>
>> On Thu, Mar 3, 2022 at 11:29 PM Jim Lemon <drjimlemon using gmail.com> wrote:
>>>
>>> Hi Neha,
>>> I think you're looking for the "cut" function.
>>>
>>> Jim
>>>
>>> On Fri, Mar 4, 2022 at 8:10 AM Neha gupta <neha.bologna90 using gmail.com> wrote:
>>>>
>>>> Hello everyone
>>>>
>>>> I have a variable with about 5000 different values
>>>>
>>>> var1= c(0, 123, 400, .....4988)
>>>>
>>>> I want to convert it into different levels for some comparisons like
>>>>
>>>> if value is between 1-100 do something
>>>> else
>>>> do other things
>>>>
>>>> Is there any sophisticated way to do that than the following:
>>>>
>>>> var2=cut(var1, br=c(-1,500, 501,1000, 1001,5000))
>>>>
>>>> Thank you
>>>>
>>>>          [[alternative HTML version deleted]]
>>>>
>>>> ______________________________________________
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> 
> ______________________________________________
> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
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> and provide commented, minimal, self-contained, reproducible code.



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