[R] result of mean(v1, v2, v3) of three real number not the same as sum(v1, v2, v3)/3

[Eric Berger]

Or ... to put it differently,, you need to wrap the numbers in c( .., ..,  )



On Thu, May 12, 2022 at 10:42 PM Ivan Krylov <krylov.r00t using gmail.com> wrote:

> On Thu, 12 May 2022 19:31:51 +0000
> "Sorkin, John" <jsorkin using som.umaryland.edu> wrote:
>
> > > mean(mlagFZ1,mlagFZ2,mlagFZ3)
> > [1] -0.3326792
>
> match.call(mean.default, quote(mean(mlagFZ1, mlagFZ2, mlagFZ3)))
> # mean(x = mlagFZ1, trim = mlagFZ2, na.rm = mlagFZ3)
>
> mean() takes a vector to compute a mean of and additional arguments,
> unlike sum(), which takes ... (almost arbitrary arguments) and sums all
> of them. Unfortunately, the "trim" argument is documented to accept any
> number and the na.rm argument is silently reinterpreted as logical in
> your case.
>
> --
> Best regards,
> Ivan
>
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