[R] detect and replace outliers by the average

[Richard O'Keefe]

What does it mean when one column is just blank, neither a
number nor NA, just nothing?

On Fri, 21 Apr 2023 at 07:08, AbouEl-Makarim Aboueissa <
abouelmakarim1962 using gmail.com> wrote:

> Dear All:  the attached file in the  .txt format
>
>
>
> *Re:* detect and replace outliers by the average
>
>
>
> The dataset, please see attached, contains a group factoring column “
> *factor*” and two columns of data “x1” and “x2” with some NA values. I need
> some help to detect the outliers and replace it and the NAs with the
> average  within each level (0,1,2) for each variable “x1” and “x2”.
>
>
>
> I tried the below code, but it did not accomplish what I want to do.
>
>
>
> The average within each level should be computed after discard the
> outliers.
>
>
>
> data<-read.csv("G:/20-Spring_2023/Outliers/data.csv", header=TRUE)
>
> data
>
> replace_outlier_with_mean <- function(x) {
>
>   replace(x, x %in% boxplot.stats(x)$out, mean(x, na.rm=TRUE))  #### ,
> na.rm=TRUE NOT working
>
> }
>
> data[] <- lapply(data, replace_outlier_with_mean)
>
>
>
>
>
> Thank you all very much for your help in advance.
>
>
>
>
>
> with many thanks
>
> abou
> ______________________
>
>
> *AbouEl-Makarim Aboueissa, PhD*
>
> *Professor, Mathematics and Statistics*
> *Graduate Coordinator*
>
> *Department of Mathematics and Statistics*
> *University of Southern Maine*
> ______________________________________________
> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

	[[alternative HTML version deleted]]