Dear all
I have this table
> dput(mat)
mat <- structure(c(2, 16, 9, 2, 16, 1, 1, 4, 7, 7, 44.52, 42.8, 43.54,
40.26, 40.09), dim = c(5L, 3L))
And I want to calculate result for contour or image plots as I did few years
ago.
However interp does not compute the z values and gives me zeros in z matrix.
library(akima)
> interp(mat[,1], mat[,2], mat[, 3], nx=5, ny=5)
$x
[1] 2.0 5.5 9.0 12.5 16.0
$y
[1] 1.0 2.5 4.0 5.5 7.0
$z
[,1] [,2] [,3] [,4] [,5]
[1,] 0 0 0 0 0
[2,] 0 0 0 0 0
[3,] 0 0 0 0 0
[4,] 0 0 0 0 0
[5,] 0 0 0 0 0
With the example from help page if less than 10 values are used, the result
is also zero
interp(akima$x[1:9], akima$y[1:9], akima$z[1:9], nx=5, ny=5)
but with 10 or more values the result is correctly calculated
interp(akima$x[1:10], akima$y[1:10], akima$z[1:10], nx=5, ny=5)
$x
[1] 0.0000 6.1625 12.3250 18.4875 24.6500
$y
[1] 1.24 5.93 10.62 15.31 20.00
$z
[,1] [,2] [,3] [,4] [,5]
[1,] NA NA NA NA 34.60000
[2,] NA NA 27.29139 27.11807 26.60971
[3,] NA 19.81371 19.63614 19.12778 18.61943
[4,] NA 14.01443 10.66531 11.13750 10.62914
[5,] NA NA NA NA NA
Help page says
x, y, and z must be the same length (execpt if x is a
SpatialPointsDataFrame) and may contain no fewer than ***four*** points.
So my understanding was that 5 poins could be used but I am obviously wrong.
Is it a bug in interp or in the documentation or is it my poor understanding
of the whole matter.
Best regards
Petr