[BioC] standard deviation from log to normal scale???
jesper.ryge at ki.se
Mon Dec 4 19:49:31 CET 2006
Here is just a lil "trivia" statistic question for the forum:-) I
apologize for my clumsy annotation but i hope I get the question
For ratios I take it its normal procedure to calculate the average as
the geometric mean. That is easiest done with log transformed values,
giving something like
<R> = mean(Ratio=a/b)=2^ (<log2(a)> - <log2(b)> + - SD)
Its the SD thats giving me a little headache as i go back to normal
(un-transformed, i use ** for annotating normal) values. SD in log
space is not symmetric in normal space, so SD** != 2^(SD)? or?
To illustrate my clumsy annotation, if : < log2(R) > + - SD(log2(R))
= 4+-1 in log space it becomes (2^4- 2^3) and 2^4+2^5 ~ 16-8 and 16
+ 32. so SD** is not symmetric.
I found 2 suggestions in the litterature that doesnt seem to account
for this asymmetry. One was giving the standard deviation of the
geometric mean to be SD**=2^(SD) just as i reasoned was inappropriate?
Another suggestion I found was for propagating errors for exponential
X = e^A, SD(X)/X = SD(A)
So should i do SD**(X) = mean(X) * SD(A) --- X ~ Ratio and A ~ log
(R) ???? again i dont see how this solved the asymmetric SD from the
Maybe i missed something basic with log-normal distributions, in any
case any help will be highly appreciated:-) I have the feeling its
rather trivial but I would really like to know how to put
(assymetric?) error bars on my (normal scale) ratios correctly. This
goes for both Affymterix summary ratios and RT-PCR ratios. What's
the correct procedure???
Dep. of Neuroscience
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