# [Rd] Calculation of e^{z^2/2} for a normal deviate z

jing hua zhao j|nghu@zh@o @end|ng |rom hotm@||@com
Fri Jun 21 17:11:43 CEST 2019

```Dear Rui,

Thanks for your quick reply -- this allows me to see the bottom of this. I was hoping we could have a handle of those p in genmoics such as 1e-300 or smaller.

Best wishes,

Jing Hua

________________________________
From: Rui Barradas <ruipbarradas using sapo.pt>
Sent: 21 June 2019 15:03
To: jing hua zhao; r-devel using r-project.org
Subject: Re: [Rd] Calculation of e^{z^2/2} for a normal deviate z

Hello,

Well, try it:

p <- .Machine\$double.eps^seq(0.5, 1, by = 0.05)
z <- qnorm(p/2)

pnorm(z)
# [1] 7.450581e-09 1.228888e-09 2.026908e-10 3.343152e-11 5.514145e-12
# [6] 9.094947e-13 1.500107e-13 2.474254e-14 4.080996e-15 6.731134e-16
#[11] 1.110223e-16
p/2
# [1] 7.450581e-09 1.228888e-09 2.026908e-10 3.343152e-11 5.514145e-12
# [6] 9.094947e-13 1.500107e-13 2.474254e-14 4.080996e-15 6.731134e-16
#[11] 1.110223e-16

exp(z*z/2)
# [1] 9.184907e+06 5.301421e+07 3.073154e+08 1.787931e+09 1.043417e+10
# [6] 6.105491e+10 3.580873e+11 2.104460e+12 1.239008e+13 7.306423e+13
#[11] 4.314798e+14

p is the smallest possible such that 1 + p != 1 and I couldn't find
anything to worry about.

R version 3.6.0 (2019-04-26)
Platform: x86_64-pc-linux-gnu (64-bit)
Running under: Ubuntu 19.04

Matrix products: default
BLAS:   /usr/lib/x86_64-linux-gnu/blas/libblas.so.3.8.0
LAPACK: /usr/lib/x86_64-linux-gnu/lapack/liblapack.so.3.8.0

locale:
[1] LC_CTYPE=pt_PT.UTF-8       LC_NUMERIC=C
[3] LC_TIME=pt_PT.UTF-8        LC_COLLATE=pt_PT.UTF-8
[5] LC_MONETARY=pt_PT.UTF-8    LC_MESSAGES=pt_PT.UTF-8
[7] LC_PAPER=pt_PT.UTF-8       LC_NAME=C
[9] LC_ADDRESS=C               LC_TELEPHONE=C
[11] LC_MEASUREMENT=pt_PT.UTF-8 LC_IDENTIFICATION=C

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods
[7] base

other attached packages:

[many packages loaded]

Hope this helps,

Rui Barradas

�s 15:24 de 21/06/19, jing hua zhao escreveu:
> Dear R-developers,
>
> I am keen to calculate exp(z*z/2) with z=qnorm(p/2) and p is very small. I wonder if anyone has experience with this?
>
> Thanks very much in advance,
>
>
> Jing Hua
>
>        [[alternative HTML version deleted]]
>
> ______________________________________________
> R-devel using r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-devel
>

[[alternative HTML version deleted]]

```

More information about the R-devel mailing list