[R] lda()

[Roger D. Peng]

I haven't done this in years but I think the `scaling' element in the 
list returned by lda is the original data matrix multiplied by the 
rotation matrix from the SVD.  Taking a look at

getAnywhere("lda.default")

will probably answer your question.

-roger

marzban wrote:
>>Perhaps some reading would be helpful.  I suggest you look first at the 
>>help file for lda().  Second, I suggest you read Venables and Ripley, MASS, 
>>4th Edition, where lda() is discussed extensively.  Third, I suggest you 
>>read Ripley's Pattern Recognition and Neural Networks, where the theory is 
>>laid out clearly.  Both of these latter books are referenced in lda's help 
>>file.
> 
> 
> I am quite familiar with all of these references. The theory behind LDA 
> is not where the problem is - I'm comfortable with that. The problem is 
> that I do not know what R is computing when it prints "Coefficients of 
> linear discriminants". (According to the source code (lda.R), it's 
> x$scaling, but I don't know what that is either.) 
> 
> 
>>Finally, you might want to tell us what version of lda() you're using, what 
>>version of R you're using, and what platform you're running on.   For all 
>>we know, you're using a 2-year old version of R and lda, both long 
>>superceded by vastly improved programs and packages. 
> 
> 
> R-1.9.1 on linux
> 
> Caren
> 
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