[R] Replace missing values in lapply

Doran, Harold HDoran at air.org
Wed Jan 24 16:50:13 CET 2007


Perfect, thxs 

> -----Original Message-----
> From: Dimitris Rizopoulos 
> [mailto:dimitris.rizopoulos at med.kuleuven.be] 
> Sent: Wednesday, January 24, 2007 10:49 AM
> To: Doran, Harold
> Cc: r-help at stat.math.ethz.ch
> Subject: Re: [R] Replace missing values in lapply
> 
> you need to return x in the function within lapply(), e.g., 
> something like
> 
> lapply(TP, function(x) { x[is.na(x)] <- 0; x })
> 
> 
> I hope it works.
> 
> Best,
> Dimitris
> 
> ----
> Dimitris Rizopoulos
> Ph.D. Student
> Biostatistical Centre
> School of Public Health
> Catholic University of Leuven
> 
> Address: Kapucijnenvoer 35, Leuven, Belgium
> Tel: +32/(0)16/336899
> Fax: +32/(0)16/337015
> Web: http://med.kuleuven.be/biostat/
>      http://www.student.kuleuven.be/~m0390867/dimitris.htm
> 
> 
> 
> ----- Original Message -----
> From: "Doran, Harold" <HDoran at air.org>
> To: <r-help at stat.math.ethz.ch>
> Sent: Wednesday, January 24, 2007 4:40 PM
> Subject: [R] Replace missing values in lapply
> 
> 
> >I have some matrices stored as elements in a list that I am working
> > with. On example is provided below as TP[[18]]
> >
> >> TP[[18]]
> >      level2
> > level1  1  2  3  4
> >     1 79  0  0  0
> >     2  0  0  0  0
> >     3  0  0  0  0
> >     4  0  0  0  0
> >
> > Now, using prop.table on this gives
> >
> >> prop.table(TP[[18]],1)
> >      level2
> > level1   1   2   3   4
> >     1   1   0   0   0
> >     2
> >     3
> >     4
> >
> > It is important for the zero's to retain their position as this 
> > matrix
> > will subsequently be used in some matrix multiplication and hence, 
> > must
> > be of dimension 4 by 4 so that is it conformable for multiplcation 
> > with
> > another matrix.
> >
> > In looking at the structure of the object resulting from prop.table 
> > I
> > see NaNs, and so I can do this
> >
> >> rr <- TP[[18]]
> >> rr[is.na(rr)] <- 0
> >> rr
> >      level2
> > level1  1  2  3  4
> >     1 79  0  0  0
> >     2  0  0  0  0
> >     3  0  0  0  0
> >     4  0  0  0  0
> >
> > This is exactly what I want for each matrix. But, I have multiple
> > matrices stored within the list that need to be changed and so I am
> > trying to resolve this via lapply, but something is awry (namely the
> > user), but I could use a little help.
> >
> > I was thinking the following function should work, but it doesn't. 
> > It
> > reduces each matrix within the list to a 0.
> >
> > PP <- lapply(TP, function(x) x[is.na(x)] <- 0)
> >
> > Am I missing something obvious?
> >
> > Harold
> >
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
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> > http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> > 
> 
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