[R] Replace missing values in lapply
Doran, Harold
HDoran at air.org
Wed Jan 24 16:50:13 CET 2007
Perfect, thxs
> -----Original Message-----
> From: Dimitris Rizopoulos
> [mailto:dimitris.rizopoulos at med.kuleuven.be]
> Sent: Wednesday, January 24, 2007 10:49 AM
> To: Doran, Harold
> Cc: r-help at stat.math.ethz.ch
> Subject: Re: [R] Replace missing values in lapply
>
> you need to return x in the function within lapply(), e.g.,
> something like
>
> lapply(TP, function(x) { x[is.na(x)] <- 0; x })
>
>
> I hope it works.
>
> Best,
> Dimitris
>
> ----
> Dimitris Rizopoulos
> Ph.D. Student
> Biostatistical Centre
> School of Public Health
> Catholic University of Leuven
>
> Address: Kapucijnenvoer 35, Leuven, Belgium
> Tel: +32/(0)16/336899
> Fax: +32/(0)16/337015
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> http://www.student.kuleuven.be/~m0390867/dimitris.htm
>
>
>
> ----- Original Message -----
> From: "Doran, Harold" <HDoran at air.org>
> To: <r-help at stat.math.ethz.ch>
> Sent: Wednesday, January 24, 2007 4:40 PM
> Subject: [R] Replace missing values in lapply
>
>
> >I have some matrices stored as elements in a list that I am working
> > with. On example is provided below as TP[[18]]
> >
> >> TP[[18]]
> > level2
> > level1 1 2 3 4
> > 1 79 0 0 0
> > 2 0 0 0 0
> > 3 0 0 0 0
> > 4 0 0 0 0
> >
> > Now, using prop.table on this gives
> >
> >> prop.table(TP[[18]],1)
> > level2
> > level1 1 2 3 4
> > 1 1 0 0 0
> > 2
> > 3
> > 4
> >
> > It is important for the zero's to retain their position as this
> > matrix
> > will subsequently be used in some matrix multiplication and hence,
> > must
> > be of dimension 4 by 4 so that is it conformable for multiplcation
> > with
> > another matrix.
> >
> > In looking at the structure of the object resulting from prop.table
> > I
> > see NaNs, and so I can do this
> >
> >> rr <- TP[[18]]
> >> rr[is.na(rr)] <- 0
> >> rr
> > level2
> > level1 1 2 3 4
> > 1 79 0 0 0
> > 2 0 0 0 0
> > 3 0 0 0 0
> > 4 0 0 0 0
> >
> > This is exactly what I want for each matrix. But, I have multiple
> > matrices stored within the list that need to be changed and so I am
> > trying to resolve this via lapply, but something is awry (namely the
> > user), but I could use a little help.
> >
> > I was thinking the following function should work, but it doesn't.
> > It
> > reduces each matrix within the list to a 0.
> >
> > PP <- lapply(TP, function(x) x[is.na(x)] <- 0)
> >
> > Am I missing something obvious?
> >
> > Harold
> >
> >
> > [[alternative HTML version deleted]]
> >
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