[R] if (cond) expr1 expr2 ??

[Ista Zahn]

Hi Tanvir,
Line breaks matter in R. If I understand correctly you want

for (i in 1: 4){
  if(i == 2){
    print("a")
    print("b")
  }
}

Best,
Ista

On Wed, Apr 13, 2011 at 10:07 PM, Mohammad Tanvir Ahamed
<mashranga at yahoo.com> wrote:
> hi , this can be done easily if (cond) expr
> ex:
>> for (i in 1: 4)+ {+ if(i==2) print("a")+ if(i==2) print("b")+ }
> output : [1] "a"[1] "b"
> but i want this
> if (cond) expr1 expr 2
> i tried this :
>> for (i in 1: 4)+ {+ if(i==2) (print("b") && print("a"))+ }
> output : [1] "b"Error in print("b") && print("a") : invalid 'x' type in 'x && y'
> but i expect the same out put as before .
> i am new at R . plz help .
> Thanks , Tanvir
>
>
>
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-- 
Ista Zahn
Graduate student
University of Rochester
Department of Clinical and Social Psychology
http://yourpsyche.org