[R] Bug in my code (finding nonzero min)

S Ellison S.Ellison at LGCGroup.com
Mon Jul 23 14:40:26 CEST 2012

```Strictly, it's calculating the minimum of the positive values in each row.

And you could do that with a bit less code using
q[,1] <- apply(remain, 1, function(x) min(x[x>0]))

> -----Original Message-----
> From: r-help-bounces at r-project.org
> [mailto:r-help-bounces at r-project.org] On Behalf Of wwreith
> Sent: 23 July 2012 05:35
> To: r-help at r-project.org
> Subject: [R] Bug in my code (finding nonzero min)
>
> Can someone verify for me if the for loop below is really
> calculating the nonzero min for each row of a matrix? I have
> a bug somewhere in the is section of code. My first guess is
> how I am find the the nonzero min of each row of my matrix.
> The overall idea is to make sure I am investing all of my
> money, i.e. new.set is a set of indicator variables for each
> stock for a particular portfolio, i.e. 0=did not buy,
> 1=bought. y are the stocks I could still buy, assuming I have
> the money, data3[,5] are their cost, so for each portfolio,
> i.e. the rows of new.set I have the option to purchase
> another stock at a cost listed in the rows of variable
> remain. Obvisouly the cheapest stock needs to have a cost>0
> in order for me to be allowed to buy it. My code is intended
> to weed out portfolios where I could have bought another
> stock, by taking budget-portfolio cost - (cheapest available
> stock) and subsetting new.set when this is negative, i.e.
> buying the cheapest available stock puts me over budget. My
> problem is that my code is still allowing examples like the
> following budget of 10, portfolio cost 6, cheapest availabe
> stock 3 despite the diff variable being negative.
>
> Any ideas?
>
> y<-1-new.set[,6:26]
> remain<-y*data3[,5]
> minn<-matrix(0,nrow(remain),1)
>
> for(q in 1:nrow(remain))
> {
>   remainc<-remain[q,]
>   minn[q,]<-min(remainc[which(remainc>0)])
> }
> maxcost<-matrix(150,nrow(new.set),1)
> diff<-maxcost[,1]-new.set[,5]-minn[,1]
> new.set<-subset(new.set,diff<0)
>
>
>
>
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