[R] shading cells in a latex table by value
Michael Friendly
friendly at yorku.ca
Wed Jul 23 18:27:02 CEST 2014
Thanks, Duncan
That's quite lovely, and makes me appreciate the tables package even more,
so I'll have to study your details.
The more general version of this idea is that rendering values in a latex
table with visual attributes (background color, font color, font family,
font shape, font weight) according to a function of the cell value
is useful in the same way as visual attributes in plots, but, at
present, far more difficult.
best,
-Michael
On 07/23/2014 11:31 AM, Duncan Murdoch wrote:
> On 23/07/2014, 9:31 AM, Michael Friendly wrote:
>> I want to create latex tables of values where the cell background is
>> shaded according to the
>> table value. For example:
>>
>> set.seed(1) # reproducibility
>> mat <- matrix(3 * rnorm(12), 3, 4)
>> rownames(mat) <- letters[1:3]
>> colnames(mat) <- LETTERS[1:4]
>>
>> > round(mat,1)
>> A B C D
>> a -1.9 4.8 1.5 -0.9
>> b 0.6 1.0 2.2 4.5
>> c -2.5 -2.5 1.7 1.2
>>
>> # colors to use: blue(+), red(-) with two shading levels,
>> # depending on abs(x) > 2
>> cols <- c(rgb(0.85,0.85,1),
>> rgb(0.7 ,0.7 ,1),
>> rgb(1,0.85,0.85),
>> rgb(1,0.7 ,0.7 ))
>> cols <- matrix(cols, 2,2)
>>
>> cellcol <- apply(mat, 1:2,
>> function(x) {i<-1+(x>0); j<-1+(abs(x)>2); cols[i,j]})
>> >
>> > cellcol
>> A B C D
>> a "#D9D9FF" "#FFB2B2" "#B2B2FF" "#D9D9FF"
>> b "#B2B2FF" "#B2B2FF" "#FFB2B2" "#FFB2B2"
>> c "#FFD9D9" "#FFD9D9" "#B2B2FF" "#B2B2FF"
>>
>> What I want is to generate a latex table of mat, with each cell colored
>> according to cellcol.
>> I can do this manually as shown below, using the latex colortbl package
>> and a macro
>> \cell{value}{color}. How can I produce this in R?
>>
>> # colortab-test.tex -----------------------
>> %% Latex part:
>>
>> \documentclass[11pt]{article}
>> \usepackage{xcolor,colortbl}
>>
>> # wrap each cell with command to define background color
>> \newcommand{\cell}[2]{\multicolumn{1}%
>> {>{\columncolor{#1}}r}{#2}}
>>
>> \definecolor{blueA}{rgb}{0.85,0.85,1}
>> \definecolor{blueB}{rgb}{0.7 ,0.7 ,1}
>> \definecolor{redA}{rgb}{1,0.85,0.85}
>> \definecolor{redB}{rgb}{1,0.7 ,0.7 }
>>
>> \begin{document}
>>
>> \begin{tabular}{lcccc}
>> & A & B & C & D \\
>> a & \cell{-1.9}{redB} & \cell{4.8}{blueA} & \cell{1.5}{blueB} &
>> \cell{-0.9}{redB} \\
>> b & \cell{0.6}{blueB} & \cell{1.0}{blueB} & \cell{2.2}{blueA} &
>> \cell{4.5}{blueA} \\
>> c \cell{-2.5}{redA} & \cell{-2.5}{redB} & \cell{1.7}{blueB} &
>> \cell{1.2}{blueB} \\
>> \end{tabular}
>> \end{document}
>> # --------------------------------------------
> You could do this using the tables package, with a custom format
> function. Normally you would calculate the table entries within the
> formula, but you can also convert a matrix.
>
> For example,
>
> colornames <- matrix(c("blueA", "blueB", "redA", "redB"),
> 2,2)
>
> myformat <- function(x) {
> i<-1+(x>0)
> j<-1+(abs(x)>2)
> paste0("\\cell{", round(x,1), "}{", colornames[cbind(i,j)], "}")
> }
>
> tab <- as.tabular(mat, like=tabular(Heading()*row ~
> Heading()*col*Format(myformat()),
> data=data.frame(row=rep(letters[1:3],4),
> col=rep(LETTERS[1:4],3))))
> latex(tab)
>
> produces
>
> \begin{tabular}{lcccc}
> \hline
> & A & B & C & \multicolumn{1}{c}{D} \\
> \hline
> a & \cell{-1.9}{blueA} & \cell{4.8}{redB} & \cell{1.5}{blueB} &
> \cell{-0.9}{blueA} \\
> b & \cell{0.6}{blueB} & \cell{1}{blueB} & \cell{2.2}{redB} &
> \cell{4.5}{redB} \\
> c & \cell{-2.5}{redA} & \cell{-2.5}{redA} & \cell{1.7}{blueB} &
> \cell{1.2}{blueB} \\
> \hline
> \end{tabular}
>
> It's a little cumbersome to tack the formatting onto an existing matrix;
> the normal expectation is that a tabular() call would be used to compute
> the cell values as well.
>
> Duncan Murdoch
--
Michael Friendly Email: friendly at yorku.ca
Professor, Psychology Dept.
York University Voice: 416 736-2100 x66249 Fax: 416 736-5814
4700 Keele Street http://datavis.ca
Toronto, ONT M3J 1P3 CANADA
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