# [R] need for help for solving operations in a vector

PIKAL Petr petr.pikal at precheza.cz
Wed Dec 30 08:28:15 CET 2015

Hi

You probably can do also only

Irig.tot <- (Irrig>HM)*6.123

to get desired vector without any further typing around.

Logical vector can be treated as c(0,1) vector. FALSE equals zero and TRUE equals 1 on calculations.

Maybe you shall spend some time reading R intro manual which can serve you as an excellent starting point to learn R. Although it has one hundred pages it is quite readable and you may find it as a best present you found under Christmas tree.

Cheers
Petr

From: Makram Belhaj Fraj [mailto:belhajfraj.makram at gmail.com]
Sent: Tuesday, December 29, 2015 9:12 PM
To: PIKAL Petr
Cc: r-help at r-project.org
Subject: RE: [R] need for help for solving operations in a vector

Hi Petr
I do thé calculation left as follows

Irrig=qWC1
Irrig [Irrig>HM]=-1
Irrig[Irrig>0]=0
Irrig.tot=-Irrig*6.123 #6.123 is the hydraulic conductivity at saturation
And I got the vector needed
Cheers
Makram
Le 28 déc. 2015 12:15, "PIKAL Petr" <petr.pikal at precheza.cz<mailto:petr.pikal at precheza.cz>> a écrit :
Hi

On top of answers you have got here is some plotting you need to answer yourself

plot(qWC1, col=(c(0, diff(qWC1))>=0 )+1)

Which from those red points you want to be included in irrigation period? All of them? Only part? Which part?

Based on your figures you probably will not get 100% correct answer.

Cheers
Petr

> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org<mailto:r-help-bounces at r-project.org>] On Behalf Of Makram
> Belhaj Fraj
> Sent: Wednesday, December 23, 2015 8:35 AM
> To: r-help at r-project.org<mailto:r-help at r-project.org>; r-help-owner at r-project.org<mailto:r-help-owner at r-project.org>
> Subject: [R] need for help for solving operations in a vector
>
>  Dear colleagues
> i need your generous help to solve the following problem
>
> I have a  soil moisture time series qWC1 (61 values)
> > qWC1
>  75.33336 75.20617 75.20617 74.95275 74.95275 74.70059 74.70059
> 74.70059
> 74.57498 74.44968 74.32469 74.07563  85.57237 90.40123 90.73760
> 90.73760 90.73760 90.73760 90.90648 91.07582 91.24564 90.90648 86.82135
> 80.69793
> 79.30393 78.62058 78.21484 77.81226 77.67876 77.41279 77.28032 76.88495
> 76.75383 76.75383 76.49260 76.36249  76.23270 76.23270 76.10325
> 75.97412
> 75.84532 75.71685  75.71685 75.71685 75.71685 75.46087 75.46087
> 75.46087
> 75.33336 75.20617 75.20617 75.20617 75.20617 75.20617 75.20617 75.07930
> 75.07930 75.07930 74.95275 74.95275  74.95275
>
> I want to measure consecutive increases corresponding to irrigation and
> consecutive decreases  corresponding to recharge I wrote the following
> code and it does not calculate for each increment in i?
> also note that I choose to not use diff command in time series because
> I  want also that "plateaux" corresponding to a minimum of 2 equal
> consecutive values are accounted as positive differences=irrigations so
> when x[i+1]==x[i] the difference y might be equal to the previous value
> xi
>
> following the code i wrote
>
> x<-ts(qWC1,start=1, end=61, frequency=1) x[1] plot(x, type="h", col =
> "green")
> y<-rep(0,61)
> for (i in 1:61) {
> if (x[i+1] > x[i]){
>     y[i]==x[i+1]-x[i]
> } else if (x[i+1]==x[i]){
>     y[i]=x[i+2]-x[i]
> } else {
>     y[i]==x[i+1]-x[i]
> }
>
> }
> plot(y, type="h", col = "blueviolet")
>
> Many thank
> Makram
>
>       [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org<mailto:R-help at r-project.org> mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> guide.html
> and provide commented, minimal, self-contained, reproducible code.

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