[R] rbind of multiple data frames by column name, when each data frames can contain different columns
John Fox
j|ox @end|ng |rom mcm@@ter@c@
Fri Jun 3 15:36:45 CEST 2022
Dear Stefano,
On 2022-06-03 8:43 a.m., Stefano Sofia wrote:
> Thank you to all who provided useful hints, great as always.
>
> In my opinion the solution given by Andrew is perfect, exactly what I wanted to do without changing the format of my data frames:
>
>
> df_list <- list(df1, df2, df3)
>
> allNms <- unique(unlist(lapply(df_list, names)))
>
> do.call(rbind, c(lapply(df_list, function(x) data.frame(x, sapply(setdiff(allNms, names(x)), function(y) NA, simplify = FALSE))), make.row.names=FALSE))
I'm moderately surprised that you find this simpler than, say,
merge(merge(df1, df2, all=TRUE), df3, all=TRUE)[allNms]
>
>
> Now I encountered this final problem: when I load my data frames in R through
>
>
> df1 <- read.table(file="/mypath/df1.csv", header = TRUE, sep=" ", dec = ".", stringsAsFactors = TRUE)
>
> df1$data_POSIX <- as.POSIXct(df1$data_POSIX, format = "%Y-%m-%d", tz="Etc/GMT-1")
>
>
> I get the following error:
>
>
> Error in data.frame(x, sapply(setdiff(allNms, names(x)), function(y) NA, :
> arguments imply differing number of rows:5, 0
>
>
> Why? df1 is a data frame correctly filled in.
I can't duplicate this error (and you don't provide the data files). A
couple of thoughts:
(1) Why set stringsAsFactors = TRUE when you plan to convert the first
column to dates (though that doesn't account for the error)?
(2) If df1.csv is really a csv file (and why use the extension .csv if
it isn't?), why specify sep=" " (though if the data file is really a csv
file, the resulting df1 would be corrupted, and you say it isn't).
Best,
John
>
>
> Thank you again
>
> Stefano
>
>
> (oo)
> --oOO--( )--OOo--------------------------------------
> Stefano Sofia PhD
> Civil Protection - Marche Region - Italy
> Meteo Section
> Snow Section
> Via del Colle Ameno 5
> 60126 Torrette di Ancona, Ancona (AN)
> Uff: +39 071 806 7743
> E-mail: stefano.sofia using regione.marche.it
> ---Oo---------oO----------------------------------------
>
>
> ________________________________
> Da: Andrew Simmons <akwsimmo using gmail.com>
> Inviato: venerd� 3 giugno 2022 11:06
> A: Stefano Sofia
> Oggetto: Re: [R] rbind of multiple data frames by column name, when each data frames can contain different columns
>
> I think I see the problem. I forgot that lapply doesn't assign names where sapply does. I think you might want to use that instead, but also supply argument simplify as FALSE
>
> sapply(setdiff(allNms, names(x)), function(y) NA, simplify = FALSE)
>
> It should produce something more like
>
> $Station2_Hs
> [1] NA
>
> $Station2_Hn
> [1] NA
>
> $Station2_flag
> [1] NA
>
> which should combine nicely with data.frame(x,)
>
>
> On Fri, Jun 3, 2022, 03:25 Stefano Sofia <stefano.sofia using regione.marche.it<mailto:stefano.sofia using regione.marche.it>> wrote:
>
> Good morning Andrew.
>
> Thank you for your help.
>
> Unfortunately your suggestion does not work, and I got different errors depending on the use of the three small examples or real data frames.
>
> If I apply your code to the three small examples I gave you (df1, df2 and df3) I get:
>
>
> Error in match.names(clabs, names(xi)) :
> names do not match previous names
>
>
> I tried to understand the origin of the problem.
>
>
> lapply(setdiff(allNms, names(x)), function(y) NA)
>
> gives
>
>
> [[1]]
> [1] NA
>
> [[2]]
> [1] NA
>
> [[3]]
> [1] NA
>
> [[4]]
> [1] NA
>
> [[5]]
> [1] NA
>
> [[6]]
> [1] NA
>
> [[7]]
> [1] NA
>
> [[8]]
> [1] NA
>
> [[9]]
> [1] NA
>
> [[10]]
> [1] NA
>
>
> and
>
> data.frame(x, lapply(setdiff(allNms, names(x)), function(y) NA))
>
> gives
>
> x NA. NA..1 NA..2 NA..3 NA..4 NA..5 NA..6 NA..7 NA..8 NA..9
> 1 1 NA NA NA NA NA NA NA NA NA NA
> 2 1 NA NA NA NA NA NA NA NA NA NA
> 3 1 NA NA NA NA NA NA NA NA NA NA
> 4 2 NA NA NA NA NA NA NA NA NA NA
> 5 2 NA NA NA NA NA NA NA NA NA NA
> 6 3 NA NA NA NA NA NA NA NA NA NA
> 7 4 NA NA NA NA NA NA NA NA NA NA
> 8 4 NA NA NA NA NA NA NA NA NA NA
> 9 4 NA NA NA NA NA NA NA NA NA NA
> 10 5 NA NA NA NA NA NA NA NA NA NA
> 11 6 NA NA NA NA NA NA NA NA NA NA
> 12 6 NA NA NA NA NA NA NA NA NA NA
> 13 6 NA NA NA NA NA NA NA NA NA NA
>
>
> Why?
>
> Unfortunately this code is too difficult for me.
>
> Sorry for bothering you, thank you for what you have already done.
>
> Stefano
>
>
> (oo)
> --oOO--( )--OOo--------------------------------------
> Stefano Sofia PhD
> Civil Protection - Marche Region - Italy
> Meteo Section
> Snow Section
> Via del Colle Ameno 5
> 60126 Torrette di Ancona, Ancona (AN)
> Uff: +39 071 806 7743
> E-mail: stefano.sofia using regione.marche.it<mailto:stefano.sofia using regione.marche.it>
> ---Oo---------oO----------------------------------------
>
>
> ________________________________
> Da: Andrew Simmons <akwsimmo using gmail.com<mailto:akwsimmo using gmail.com>>
> Inviato: gioved� 2 giugno 2022 08:21
> A: Stefano Sofia
> Oggetto: Re: [R] rbind of multiple data frames by column name, when each data frames can contain different columns
>
> I would change this:
> do.call(rbind, c(lapply(df_list, function(x) data.frame(c(x, sapply(setdiff(allNms, names(x)), function(y) NA)))), make.row.names=FALSE))
> to:
> do.call(rbind, c(lapply(df_list, function(x) data.frame(x, lapply(setdiff(allNms, names(x)), function(y) NA))), make.row.names=FALSE))
>
>
> On Thu, Jun 2, 2022, 02:13 Stefano Sofia <stefano.sofia using regione.marche.it<mailto:stefano.sofia using regione.marche.it>> wrote:
> Dear R-list users,
>
> for each winter season from 2000 to 2022 I have a data frame collecting for different weather stations snowpack height (Hs), snowfall in the last 24h (Hn) and a validation flag.
>
> Suppose I have these three following data frames
>
>
> df1 <- data.frame(data_POSIX=seq(as.POSIXct("2000-12-01", format="%Y-%m-%d", tz="Etc/GMT-1"), as.POSIXct("2000-12-05", format="%Y-%m-%d", tz="Etc/GMT-1"), by="1 days"), Station1_Hs = c(30, 40, 50, NA, 55), Station1_Hn = c(10, 20, 10, NA, 5), Station1_flag = c(0, 0, 0, NA, 0), Station2_Hs = c(20, 20, 30, 30, 0), Station2_Hn = c(0, 0, 10, 0, 5), Station2_flag = c(0, 0, 0, 1, 0))
>
>
> df2 <- data.frame(data_POSIX=seq(as.POSIXct("2001-12-01", format="%Y-%m-%d", tz="Etc/GMT-1"), as.POSIXct("2001-12-05", format="%Y-%m-%d", tz="Etc/GMT-1"), by="1 days"), Station1_Hs = c(50, 60, 70, NA, NA), Station1_Hn = c(20, 20, 20, NA, NA), Station1_flag = c(0, 0, 0, NA, NA), Station3_Hs = c(20, 20, 30, 30, 0), Station3_Hn = c(0, 0, 10, 0, 5), Station3_flag = c(0, 0, 0, 1, 0))
>
>
> df3 <- data.frame(data_POSIX=seq(as.POSIXct("2002-12-01", format="%Y-%m-%d", tz="Etc/GMT-1"), as.POSIXct("2002-12-05", format="%Y-%m-%d", tz="Etc/GMT-1"), by="1 days"), = c(0, 0, 0, NA, NA), Station3_Hs = c(20, 20, 30, 30, 0), Station3_Hn = c(0, 0, 10, 0, 5), Station3_flag = c(0, 0, 0, 1, 0))
>
>
> As you can see, each data frame can have different stations loaded.
>
> I would need to call rbind matching data frames by column name (i.e. by station name), keeping in mind that the number of stations loaded in each data frame may differ. The result should be
>
> data_POSIX Station1_Hs Station1_Hn Station1_flag Station2_Hs Station2_Hn Station2_flag Station3_Hs Station3_Hn Station3_flag
> 2000-12-01 30 10 0 20 0 0 NA NA NA
> 2000-12-02 40 20 0 20 0 0 NA NA NA
> 2000-12-03 50 10 0 30 10 0 NA NA NA
> 2000-12-04 NA NA NA 30 0 0 NA NA NA
> 2000-12-05 55 5 0 0 5 0 NA NA NA
> 2001-12-01 50 20 0 NA NA NA 20 0 0
> 2001-12-02 60 20 0 NA NA NA 20 0 0
> 2001-12-03 70 20 0 NA NA NA 30 10 0
> 2001-12-04 NA NA NA NA NA NA 30 0 1
> 2001-12-05 NA NA NA NA NA NA 0 5 0
> 2002-12-01 NA NA NA 50 20 0 20 0 0
> 2002-12-02 NA NA NA 60 20 0 20 0 0
> 2002-12-03 NA NA NA 70 20 0 30 10 0
> 2002-12-04 NA NA NA NA NA NA 30 0 1
> 2002-12-05 NA NA NA NA NA NA 0 5 0
>
> I tried this code
>
> df_list <- list(df1, df2, df3)
> allNms <- unique(unlist(lapply(df_list, names)))
> do.call(rbind, c(lapply(df_list, function(x) data.frame(c(x, sapply(setdiff(allNms, names(x)), function(y) NA)))), make.row.names=FALSE))
>
> but I get this error:
> Error in (function (..., row.names = NULL, check.rows = FALSE, check.names = TRUE, :
> arguments imply differing number of rows
>
> Could someone please help me?
>
>
> Thank you for your attention
>
> Stefano
>
>
> (oo)
> --oOO--( )--OOo--------------------------------------
> Stefano Sofia PhD
> Civil Protection - Marche Region - Italy
> Meteo Section
> Snow Section
> Via del Colle Ameno 5
> 60126 Torrette di Ancona, Ancona (AN)
> Uff: +39 071 806 7743
> E-mail: stefano.sofia using regione.marche.it<mailto:stefano.sofia using regione.marche.it>
> ---Oo---------oO----------------------------------------
>
> ________________________________
>
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> ______________________________________________
> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
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--
John Fox, Professor Emeritus
McMaster University
Hamilton, Ontario, Canada
web: https://socialsciences.mcmaster.ca/jfox/
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