[R] Is there any design based two proportions z test?

[Anthony Damico]

hi, this guide to analyzing changes in prevalence rates over time with
complex survey data might also help?  thanks

http://asdfree.com/trend-analysis-of-complex-survey-data.html



On Wed, Jan 17, 2024, 9:15 AM John Fox <jfox using mcmaster.ca> wrote:

> Dear Md Kamruzzaman,
>
> To answer your second question first, you could just use the svychisq()
> function. The difference-of-proportion test is equivalent to a chisquare
> test for the 2-by-2 table.
>
> You don't say how you computed the confidence intervals for the two
> separate proportions, but if you have their standard errors (and if not,
> you should be able to infer them from the confidence intervals) you can
> compute the variance of the difference as the sum of the variances
> (squared standard errors), because the two proportions are independent,
> and from that the confidence interval for their difference.
>
> I hope this helps,
> John
> --
> John Fox, Professor Emeritus
> McMaster University
> Hamilton, Ontario, Canada
> web: https://www.john-fox.ca/
>
> On 2024-01-16 10:21 p.m., Md. Kamruzzaman wrote:
> > [You don't often get email from mkzaman.m using gmail.com. Learn why this is
> important at https://aka.ms/LearnAboutSenderIdentification ]
> >
> > Caution: External email.
> >
> >
> > Hello Everyone,
> > I was analysing big survey data using survey packages on RStudio. Survey
> > package allows survey data analysis with the design effect.The survey
> > package included functions for all other statistical analysis except
> > two-proportion z tests.
> >
> > I was trying to calculate the difference in prevalence of Diabetes and
> > Prediabetes between the year 2011 and 2017 (with 95%CI). I was able to
> > calculate the weighted prevalence of diabetes and prediabetes in the Year
> > 2011 and 2017 and just subtracted the prevalence of 2011 from the
> > prevalence of 2017 to get the difference in prevalence. But I could not
> > calculate the 95%CI of the difference in prevalence considering the
> weight
> > of the survey data.
> >
> > I was also trying to see if this difference in prevalence is
> statistically
> > significant. I could do it using the simple two-proportion z test without
> > considering the weight of the sample. But I want to do it considering the
> > weight of the sample.
> >
> >
> > Example: Prevalence of Diabetes:
> >                                                       2011: 11.0 (95%CI
> > 10.1-11.9)
> >                                                       2017: 10.1 (95%CI
> > 9.4-10.9)
> >                                                       Diff: 0.9% (95%CI:
> ??)
> >                                                       Proportion Z test P
> > Value: ??
> > Your cooperation will be highly appreciated.
> >
> > Thanks in advance.
> >
> > With Regards
> >
> > *--------------------------------*
> >
> > *Md Kamruzzaman*
> >
> > *PhD **Research Fellow (**Medicine**)*
> > Discipline of Medicine and Centre of Research Excellence in Translating
> > Nutritional Science to Good Health
> > Adelaide Medical School | Faculty of Health and Medical Sciences
> > The University of Adelaide
> > Adelaide SA 5005
> >
> >          [[alternative HTML version deleted]]
> >
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> ______________________________________________
> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
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>

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